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3 years ago

What is the formula for sodium sulfate? a. na(so) b. naso c. naso d. na(so)?

Chemistry

1 answer:

Luden [163]3 years ago

8 0

The formula for sodium sulfate is na(so)

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Be + O2 --> BeO Balance this and what's the type of reaction?

max2010maxim [7]

Answer:

2Be + O2 = 2BeO

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Explanation:

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2 years ago

What kind of charge does a neutron have?

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3 years ago

If an electron fell to a lower orbit or energy level, energy would be

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It would emit energy in most of the cases in form of light

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4 years ago

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The concentration of sugar in Coke is approximately 10%, or 100 ppt. If you drink

masya89 [10]

Answer:

35.5g of sugar

Explanation:

To solve this question we must assume the density of coke = Density of water = 1g/mL

Thus, in a single can of coke, the mass is 355g. Now, the 10% of this coke is sugar. That means the amount of sugar you are consuming is:

355g * (10/100) = 35.5g of sugar

10/100 = 10%

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3 years ago

Gold has a density of 1,200 lb./ft. What is the density of gold in g/em? For conversion factors use I lb. 453.6 g, and l inch-2.

Jlenok [28]

Answer: The density of gold in $g/cm^3$ is $19.22g/cm^3$

Explanation:

Density is defined as the ratio of mass of the object and volume of the object. Mathematically,

$\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}$

We are given:

Density of gold = $1200lb/ft^3$

Using conversion factors:

1 lb = 453.6 g

1 feet = 12 inches

1 inch = 2.54 cm

Converting given quantity into $g/cm^3$ , we get:

$\Rightarrow (\frac{1200lb}{ft^3})\times (\frac{453.6g}{1lb})\times (\frac{1ft}{12inch})^3\times (\frac{1inch}{2.54cm})^3\\\\\Rightarrow 19.22g/cm^3$

Hence, the density of gold in $g/cm^3$ is $19.22g/cm^3$

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4 years ago