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3 years ago

Why is the wavelength of 633 nm used to analyze the standard solutions and drink samples?

Chemistry

1 answer:

RUDIKE [14]3 years ago

6 0

Answer:

Corresponding with orange light, is the wavelength that blue solutions absorb the most.

Explanation:

If light is diffused through a solution of a given color, emerges of light from another wavelength is consumed and fades away. However, the wavelength of light relating to the color of such a solution is transferred. The color of the light is consumed is usually the contrasting one being transferred. As seen in a color wheel where, blue complement orange, red complement green, and yellow complement violet.

Thus, for a blue substance in solution, its complementary color is said to be orange, Given that the wavelength of orange color varies from 600 - 640 nm where it's maximum absorbance is approximately 633 nm. This wavelength is what is employed when analyzing the standard solutions and drink samples.

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3 years ago

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How many grams of sucrose (C12H22O11) are in 1.55 L of 0.758 M sucrose solution?

victus00 [196]

Answer:

Mass of Sucrose in given Solution is 401.8158 grams.

Explanation:

Given,

Molarity of Sucrose Solution = 0.758 M.

Volume of Sucrose Solution(V) = 1.55 L.

To find the mass of Sucrose in the solution, we need to find the number of moles of Sucrose present in the given solution 0f 0.758 M.

c = 0.758 M

number of moles can be calculated using

n = c*V

n= 0.758*1.55 = 1.1749 moles

Then to convert no, of moles to mass, we can use the formula,

number of moles(n) = Mass(m)/Molar Mass(M)

The Molar mass of Sucrose C₁₂H₂₂O₁₁ is

Mass of Carbon Sucrose = 12*12 = 144 grams

Mass of Hydogen in Sucrose = 1*22 = 22 grams

Mass of Oxygen in Sucrose = 16*11 = 176 grams

Molar mass of Sucrose = 144 + 22 +176 = 342 grams.

Substituting the values in the formula,

number of moles(n) = Mass(m)/Molar Mass(M)

we get,

1.1749 = (m)/342 => m = 1.1749 *342 = 401.8158 grams.

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3 years ago

What is the law of chemical equivalent?

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Photochemical equivalence law

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3 years ago

A 250 mL solution of common salt and water was prepared so that the concentration of the solution in terms of mass of volume per

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Answer:

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Explanation:

Why is a written contract almost always better than an oral contract?

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3 years ago

Consider a sample of 10.0 g of the gaseous hydrocarbon C2H6 to answer the following question: How many moles are present in this

Masja [62]

<u>Answer:</u> The moles of given hydrocarbon is 0.3 moles

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

We are given:

Given mass of ethane = 10.0 g

Molar mass of ethane = $[(2\times 12)+(6\times 1)]=30g/mol$

We need to divide the given value by the molar mass.

Putting values in above equation, we get:

$\text{Moles of ethane}=\frac{10.0g}{30g/mol}=0.3mol$

In case of multiplication and division, the number of significant digits is taken from the value which has least precise significant digits. Here, the least precise number of significant digits are 1.

Hence, the moles of given hydrocarbon is 0.3 moles

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