Answer:
0.1988 J/g°C
Explanation:
-Qmetal = Qwater
Q = mc∆T
Where;
Q = amount of heat
m = mass of substance
c = specific heat of substance
∆T = change in temperature
Hence;
-{mc∆T} of metal = {mc∆T} of water
From the information provided in this question, For water; m= 22.0g, ∆T = (24°C-19°C), c = 4.18J/g°C.
For metal; m= 34.0g, ∆T = (24°C-92°C), c = ?
Note that, the final temperature of water and the metal = 24°C
-{34 × c × (24°C-92°C)} = 22 × 4.18 × (24°C-19°C)
-{34 × c × (-68°C)} = 459.8
-{34 × c × -68} = 459.8
-{-2312c} = 459.8
+2312c = 459.8
c = 459.8/2312
c = 0.1988
The specific heat capacity of the metal is 0.1988 J/g°C
I believe it's about the dislodging response as Ag structures solvent salt with nitrate. For dislodging response, more receptive metal will uproot less receptive metal from the arrangement. In your question, the reactivity of the metal are positioned as takes after: Mg > Cu > Ag. Take note of that more responsive metals, that are Mg and Cu, are in the arrangement.
Atmospheric pressure from barometer = (9810) × (13.6) × (0.720) = 96060 Pa = 96.06 kPa Absolute pressure in compartment A, 496.06 kPa P = P + P abs, A gauge, A atm = 400 + 96.06 = Absolute Pressure from barometer
The answer is CI because that is the largest
Answer:
I would go with tododeku to leave room for kiribaku but that's my opinion
Just because I ship that doesn't mean i don't secretly ship bakudeku
Explanation:
Bakudeku is a hawt ship and I love it so friggen much, but kiribaku is kinda cute and it got me all mixed up. I'm in a mess as well trying to figure out a solid ship for each character. I'm procrastinating by drawing a bunch of random fanart.
