Answer:
+0.52m
Explanation:
The force applied by the archer is directly proportional to the displacement of the bow string provided the elastic limit of the string is not exceeded.
= kx
k = string constant
x = string extension
x = +0.5185m
x = +0.52m
The displacement of the bow string is +0.52m
Answer:
A) m = 1600 kg
, B) p = 3.2 10⁴ kg m / s
, C) Δp = - 3.2 10⁴ kg m / s
D) t = 51.6 s
Explanation:
A) They indicate the weight of the vehicle W = 15680 N
weight is the attraction of the earth on a body
W = m g
m = W / g
m = 15680 / 9.8
m = 1600 kg
B) The momentum is defined by
p = m v
p = 1600 20
p = 3.2 10⁴ kg m / s
C) the moment change is
Δp = p_{f} -p₀
as the vehicle stops the final speed is zero and therefore the moment is zero
ΔP = 0 - p₀
Δp = - 3.2 10⁴ kg m / s
D) Let's use Newton's second law
F = m a
a = F / m
a = 6.2 102/1600
a = 0.3875 m / s²
Now we can use kinematics, note that as the vehicle stops, the relationship must be opposite to the speed
v = v₀ - a t
v = 0
0 = v₀ - a t
t = v₀ / a
t = 20 / 0.3875
t = 51.6 s
Answer:
This is because, when an object which has possessed kinetic energy under its being in motion hits another object, which is stationary the object at rest receives part of the energy inherent in the body which has kinetic energy and expresses the received energy in the form of motion or some forms different from the initial stationary position.
Explanation:
Answer:
38,437.5
Explanation:
Density(d)= 102.5g/ml
Volume (v)=375ml
Mass(m) = ?
D =m/v
102.5= m/375
102.5*375=m
38,437.5=m
therefore Mass = 38,437.5g/ml.
Answer:
60
Explanation:
Translation -
A book weighing 12 N is balanced on a table. Knowing that the static friction coefficient is 0.5, how much is the friction force worth?
Friction force is
f = u * n
f = 0.5 * 12N
f = 60
