Answer:
Clyde will provide greater impulse
Explanation:
We have given that Al exerts a force of 200 N for 5 sec
We know that impulse is given by, impulse = force ×time = 200×5 =1000 N-s
Bill exerts a force of 500 N for 2 sec
So impulse = 500×2 = 1000 N-s
Now the force exerted by Clyde 300 N for 4 sec
So impulse = 300×4 = 1200 N-s
From above calculation we can see that Clyde provide greater impulse than any other
Answer:
280 N
Explanation:
Applying Newton's third second law of motion,
F = m(v-u)/t................... Equation 1
Where F = Magnitude of the average force on the ball during contact, v = final velocity of the ball, u = initial velocity of the ball, t = time of contact of the ball and the wall.
Note: Let the direction of the initial velocity of the ball be positive
Given: m = 4 kg, u = 3.0 m/s, v = -4.0 m/s (bounce off), t = 0.1 s
Substitute into equation 1
F = 4(-4-3)/0.1
F = 4(-7)/0.1
F = -28/0.1
F = -280 N.
Note: The negative sign tells that the force on the ball act in opposite direction to the initial motion of the ball
I believe another name for lower point is Ice point
By heat or change in matter,
there can be different reactions that create heat (like exothermic or endothermic reactions)
or movement can give off energy too,
energy is basically just heat
Answer:
and 20.86 seconds are the values of the rate constant and the half-life for this process respectively..
Explanation:
Expression for rate law for first order kinetics is given by:
where,
k = rate constant
t = age of sample
= let initial amount of the reactant
a = amount left after decay process
We have :
t = 95 s
Half life is given by for first order kinetics::
and 20.86 seconds are the values of the rate constant and the half-life for this process respectively..
