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kozerog [31]
4 years ago
14

What is the distance between (-5,5) and (2,6) rounding to the nearest hundred

Mathematics
1 answer:
ExtremeBDS [4]4 years ago
5 0
\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -5}}\quad ,&{{ 5}})\quad 
%  (c,d)
&({{ 2}}\quad ,&{{ 6}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
d=\sqrt{[2-(-5)]^2+[6-5]^2}\implies d=\sqrt{(2+5)^2+(6-5)^2}
\\\\\\
d=\sqrt{7^2+1^2}\implies d=\sqrt{50}
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Answer:

Step-by-step explanation:

1.4% of b = \frac{1.4}{100}*b = 0.014b

8% of x = \frac{8}{100}*x = 0.08x

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Step-by-step explanation:

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6 0
3 years ago
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A bullet is fired straight up from a gun with initial velocity 1120 feet per second at an initial height of 8 feet. Use the form
Dafna1 [17]

Answer:

70 seconds

Step-by-step explanation:

Given that;

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Thus;

Replacing the value of v_o =  1120 and h = 0 (i.e. when h =0) in the above expression; we have:

0= -16t^2 +(1120)t + 8

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mulitiply through by (-)

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Divide through by 8

= 2t² -  140t - 1

The above expression forms a quadratic equation.

where;

a = 2

b = -140

c = - 1

So, by using the quadratic formula \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}, we have:

= \dfrac{-(-140) \pm \sqrt{(-140)^2-4(2)(-1)}}{2(2)}

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= \dfrac{140 \pm \sqrt{19608}}{4}

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=\dfrac{280}{4} \ \ \ OR \ \ \  0

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6 0
3 years ago
Can anybody help with this one ...... ?
VLD [36.1K]

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Step-by-step explanation:

8 0
3 years ago
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vichka [17]
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