1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
hichkok12 [17]
3 years ago
8

Which effects result from the influence of media and technology on children

Physics
1 answer:
Salsk061 [2.6K]3 years ago
6 0
Can cause children into getting cyber bullying, being a thief, sexual behavior, anxiety, and depression
You might be interested in
Please help ill mark youas brainliest !!
USPshnik [31]

Answer:

can you put on a clearer image this one is hard to see

8 0
2 years ago
Two pool balls, each moving at 2 m/s, roll toward each other and collide. Suppose after bouncing apart, each moves at 2 m/s. Thi
stira [4]

Answer:D

Explanation:according to the law of conservation of energy/momentum, when two bodies collides, their total momentum and energy before and after collision are equal. Given that the two bodies move with the same velocities after collision, means that the law has not been violated since momentum = mass x velocity (where mass is constant)

4 0
3 years ago
What is the mass of a person running at 2.5 m/s with momentum of<br> 200 kg m/S
kondor19780726 [428]

Answer:

m = 80 kg

Explanation:

p = m × v

200 = m × 2.5

2.5m = 200

m = 200/2.5

m = 80 kg

5 0
3 years ago
Where in a river would you find fish that are adapted to low light and low oxygen levels?
snow_tiger [21]
The dead Zone is where you were find fish that are adapted to low light and low oxygen levels. 
7 0
3 years ago
The cue ball is deflected so that it makes an angle of 30.0° with its original direction of travel.
Alexus [3.1K]

Answer:

(a) θ= 43.89°

(b) v_{1} = 1.88\sqrt{3} \frac{m}{s}

    v_{2} = 6.79 \frac{m}{s}

Explanation:

Ball 1:

u_{1} = 7.52\frac{m}{s}

Ball 2:

u_{2} = 0\frac{m}{s}

As the collision is elastic, it means that kinetic energy and momentum are conserved. Following that, we apply the law of conservation of energy and momentum:

\frac{1}{2} m_{1}u_{1}^{2}   = \frac{1}{2} m_{1}v_{1}^{2} + \frac{1}{2} m_{2}v_{2}^{2}

and

m_{1}u_{1} =   m_{1}v_{1} + m_{2}v_{2}

Where u is the velocity before the collision, and v are the velocities after the collision. Both previous equations can be simplified as:

u_{1}^{2}   = v_{1}^{2} + v_{2}^{2}

and

u_{1} =   v_{1} + v_{2}

This because the two balls have the same mass. We know that the cue ball is deflected and makes an angle of 30°. From conservation in x-direction, we get::

56.55 = v_{1} ^{2} + v_{2} ^{2}

and

u_{1} = v_{1}cos(30) +  v_{2}cos(\theta)

Solving we get:

(\frac{2u_{1}-\sqrt{3}v_{1}  }{2cos(\theta)})^{2}  = 56.55-v_{1} ^{2}

From conservation in y-direction, we get:

0 = v_{1}sin(30) -  v_{2}sin(\theta)

From this, we solve this equation system and get the answers. Remember to add 30° to the angle obtained.

8 0
3 years ago
Other questions:
  • What is the volume of an object that has a density of 65g/cm3 and a mass of 130g.
    12·1 answer
  • If you increase the force exerted on an object, what will happen to the acceleration?
    9·1 answer
  • Planets in our solar system do not revolve around the sun in perfect circles. Their orbits are more like ovals that scientists d
    8·1 answer
  • What is the volume of a stopper that has a mass of 57 grams and a density of 8.4 g/cm3?
    15·1 answer
  • Incident beam<br> Which order is the brightest?
    13·1 answer
  • A car is moving at 11m/s and has a mass of 1200 kg. What is the momentum of her car?
    13·1 answer
  • Help Please! a lot of points for 3 questions
    14·1 answer
  • Which of the following are single-displacement reactions?
    8·2 answers
  • A stone is thrown horizontally from the top of a tower at the same instant a ball is droppedvertically. Which object is travelin
    7·1 answer
  • An object traveling at a constant
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!