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ch4aika [34]
3 years ago
11

A golf ball is struck with a five iron on level ground. it lands 100.0 m away 4.60 s later. what was the magnitude and direction

of the initial velocity? (neglect air resistance.)
Physics
1 answer:
finlep [7]3 years ago
6 0

consider the motion in x-direction

v_{ox} = initial velocity in x-direction = ?

X = horizontal distance traveled = 100 m

a_{x} = acceleration along x-direction = 0 m/s²

t = time of travel = 4.60 sec

Using the equation

X = v_{ox} t + (0.5) a_{x} t²

100 =  v_{ox} (4.60)

v_{ox} = 21.7 m/s


consider the motion along y-direction

v_{oy} = initial velocity in y-direction = ?

Y = vertical displacement  = 0 m

a_{y} = acceleration along x-direction = - 9.8 m/s²

t = time of travel = 4.60 sec

Using the equation

Y = v_{oy} t + (0.5) a_{y} t²

0 = v_{oy} (4.60) + (0.5) (- 9.8) (4.60)²

v_{oy} = 22.54 m/s

initial velocity is given as

v_{o} = sqrt((v_{ox})² + (v_{oy})²)

v_{o} = sqrt((21.7)² + (22.54)²) = 31.3 m/s

direction: θ = tan⁻¹(22.54/21.7) = 46.12 deg

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A proton travels with a speed of 4.2×106 m/s at an angle of 30◦ west of north. A magnetic field of 2.5 T points to the north. Fi
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Answer:

8.4\cdot 10^{-13} N

Explanation:

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v=4.2\cdot 10^6 m/s is the proton velocity

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\theta=30^{\circ} is the angle between the direction of v and B

Substituting into the formula, we find

F=(1.6\cdot 10^{-19}C)(4.2\cdot 10^6 m/s)(2.5 T) sin 30^{\circ}=8.4\cdot 10^{-13} N

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In a study conducted by a University of Illinois researcher, the football team at Unity High School in Tolono, IL was equipped f
Angelina_Jolie [31]

The duration (i.e time) of the impact, given that the head impact was 1770 N is 0.005 s

<h3>How do I determine the duration (i.e time)?</h3>

Impulse is defined as the change in momentum of an object. It is expressed as:

Impulse = change in momentum

Impulse = final momentum – Initial momentum

Impule = m(v - u)

Impulse = force × time

Impulse = Ft

Thus,

Ft = m(v - u)

Where

  • F is the force
  • t is the time
  • m is the mass
  • u is the initial velocity
  • v is the final velocity

Now, we can obtain the duration (i.e time) of the impact. Details below:

  • Force (F) = 1770 N
  • Initial velocity = 2.09 m/s
  • Mass (m) = 4.12 Kg
  • Final velocity = 0 m/s
  • Duration (t) =?

Ft = m(v + u) since the collision came to a stop

1770 × t = 4.12 × (0 + 2.09)

1770 × t = 4.12 × 2.09

Divide both sides by 1770

t = (4.12 × 2.09) / 1770

t = 0.005 s

Thus, the duration is 0.005 s

Learn more about time:

brainly.com/question/64749

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4 0
3 years ago
Light of wavelength 480 nm illuminates a double slit, and the interference pattern is observed on a screen. At the position of t
vova2212 [387]

Answer:

BC =980nm

Explanation:

Given wavelength =490nm

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Required to find (OB - OC) = BC (more distant slit - nearest slit ) = dsin theta

We have dsin theta = m*wavelength

or BC = m* wavelength = 2*490nm

= 980nm = 98.000A

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3 years ago
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