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FinnZ [79.3K]
3 years ago
14

A motorbike accelerates from rest at 12m/s in 3s on a level road. If the force is 3000n what is the total mass of the cyclist an

d the motorbike?
Physics
2 answers:
AnnyKZ [126]3 years ago
5 0
A( Acceleration)= 12m/s
F(Force)= 3000N
M(Mass)=?

You Know, F= MA (Force= Mass x Acceleration)
then M= ?

stira [4]3 years ago
3 0
We know that:
a=(v-u)/t
a=(12m/s-0)/3s
a=4m/s²
Now:
F=ma
3000N=m*4m/s²
3000N/4m/s²=m
m=750kg
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A young woman with normal distant vision has a 10.0% ability to accommodate (that is, increase) the lens strength (a.k.a, lens p
Kipish [7]

Answer:

20.0 cm

Explanation:

Here is the complete question

The normal power for distant vision is 50.0 D. A young woman with normal distant vision has a 10.0% ability to accommodate (that is, increase) the power of her eyes. What is the closest object she can see clearly?

Solution

Now, the power of a lens, P = 1/f = 1/u + 1/v where f = focal length of lens, u = object distance from eye lens and v = image distance from eye lens.

Given that we require a 10 % increase in the power of the lens to accommodate the image she sees clearly, the new power P' = 50.0 D + 10/100 × 50 = 50.0 D + 5 D = 55.0 D.

Also, since the object is seen clearly, the distance from the eye lens to the retina equals the distance between the image and the eye lens. So, v = 2.00 cm = 0.02 m

Now, P' = 1/u + 1/v

1/u = P'- 1/v

1/u = 55.0 D - 1/0.02 m

1/u = 55.0 m⁻¹ - 1/0.02 m

1/u = 55.0 m⁻¹ - 50.0 m⁻¹

1/u = 5.0 m⁻¹

u = 1/5.0 m⁻¹

u = 0.2 m

u = 20 cm

So, at 55.0 dioptres, the closet object she can see is 20 cm from her eye.

8 0
2 years ago
What is the maximum value the string tension can have before the can slips? The coefficient of static friction between the can a
Naya [18.7K]

Answer:

T= 38.38 N

Explanation:

Here

mass of can = m = 3 kg

g= 9.8 m/sec2

angle θ = 40°

From figure we see the vertical and horizontal component of tension force T

If the can is to slip - then horizontal component of tension force should become equal to force of friction.

First we find force of friction

Fs= μ R

where

μ = 0.76

R = weight of can = mg = 3 × 9.8 = 29.4 N

Now horizontal component of tension

Tx= T cos 40 = T× 0.7660  N

==>T× 0.7660 = 29.4

==> T= 38.38 N

8 0
3 years ago
I NEED HELP
Oduvanchick [21]

Answer:

the answer is different

Explanation:

i took the test

3 0
3 years ago
Given the following specific heat capacities, which material was have the largest change in temperature if 10 grams of each subs
Ilya [14]

Answer:

Explanation:

Comment

You could calculate it out by assuming the same starting temperature for each substance. (You have to assume that the substances do start at the same temperature anyway).

That's like shooting 12 with 2 dice. It can be done, but aiming for a more common number is a better idea.

Same with this question.

You should just develop a rule.  The rule will look like this

The greater the heat capacity the (higher or lower) the change in temperature.

The greater the heat capacity the lower the change in temperature

That's not your question. You want to know which substance will have the greatest temperature change given their heat capacities.

Answer

lead. It has the smallest heat capacity and therefore it's temperature change will be the greatest.

5 0
2 years ago
Read 2 more answers
You travel down the highway at a steady rate of 75 mph (33.53 m/s)  for a total of 25 minutes, calculate how far you traveled i
Dima020 [189]

Answer:

50280 meters

Explanation:

33.52 meters/seconds is 2011.2 meters/minutes (multiply by 60)

2011.2 meters/m * 25 minutes = answer

3 0
3 years ago
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