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Hoochie [10]
2 years ago
14

A space probe is coasting through space at a steady speed of 100p feet per second. the booster rocket fires for 1/2 seconds so t

he price is now Traveling at 5.000 feet per second. What acceleration did the socket deliver?
Physics
1 answer:
aleksandr82 [10.1K]2 years ago
6 0

Answer:

Acceleration: 9800 ft/s^2

Explanation:

The acceleration of an object is equal to the rate of change of velocity:

a=\frac{v-u}{t}

where

u is the initial velocity

v is the final velocity

t is the time taken for the velocity to change from u to v

For the space probe in this problem, we have:

u = 100 ft/s (initial velocity)

v = 5000 ft/s (final velocity)

t = 0.5 s (time taken)

Therefore, the acceleration is

a=\frac{5000-100}{0.5}=9800 ft/s^2

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