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3 years ago

¿De qué manera puedo identificar ácidos y bases en la vida cotidiana?

Chemistry

1 answer:

inna [77]3 years ago

4 0

Answer:

Ya sea que explore su cocina, su baño o su cuarto de lavado, encontrará excelentes ejemplos de ácidos y bases a su alrededor. La escala de pH es un concepto importante tanto dentro como fuera del laboratorio de química.

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How many sodium atoms does 2NaOH have?

attashe74 [19]

Answer:

Explanation:

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3 years ago

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How does H2So4 break up to h+ & hso4 - ?

Katena32 [7]

H2So4 is a strong acid and a strong electrolyte which means that when this dissociates in water, the dissociation process is complete. The first dissociation is

H2 SO4 = H + HSO4-

This can further release H+ and dissociate SO4- instead already

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3 years ago

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3 years ago

A buffer solution contains 0.496 M hydrocyanic acid and 0.399 M sodium cyanide . If 0.0461 moles of sodium hydroxide are added t

pochemuha

Answer : The pH of the solution is, 9.63

Explanation : Given,

The dissociation constant for HCN = $pK_a=9.31$

First we have to calculate the moles of HCN and NaCN.

$\text{Moles of HCN}=\text{Concentration of HCN}\times \text{Volume of solution}=0.496M\times 0.225L=0.1116mole$

and,

$\text{Moles of NaCN}=\text{Concentration of NaCN}\times \text{Volume of solution}=0.399M\times 0.225L=0.08978mole$

The balanced chemical reaction is:

$HCN+NaOH\rightarrow NaCN+H_2O$

Initial moles 0.1116 0.0461 0.08978

At eqm. (0.1116-0.0461) 0 (0.08978+0.0461)

0.0655 0.1359

Now we have to calculate the pH of the solution.

Using Henderson Hesselbach equation :

$pH=pK_a+\log \frac{[Salt]}{[Acid]}$

Now put all the given values in this expression, we get:

$pH=9.31+\log (\frac{0.1359}{0.0655})$

$pH=9.63$

Therefore, the pH of the solution is, 9.63

4 0

3 years ago

What is the amount of heat energy absorbed when 36 grams of ice at -20oC is melted to water at 0oC?

Ulleksa [173]

Answer:

Q = 1461.6 J

Explanation:

Given data:

Mass of ice = 36 g

Initial temperature = -20°C

Final temperature = 0°C

Amount of heat absorbed = ?

Solution:

specific heat capacity of ice is 2.03 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 0°C - (-20°C)

ΔT = 20°C

Q = 36 g ×2.03 j/g.°C×20°C

Q = 1461.6 J

3 0

2 years ago

¿De qué manera puedo identificar ácidos y bases en la vida cotidiana?​

¿De qué manera puedo identificar ácidos y bases en la vida cotidiana?