Answer:
a) the atomic number is 15
b) the mass number is 15+16 = 31
c) element is phosphorus
d)Group 15 period 3
The most appropriate answer is C !! Cs is most electropositive and thus least electronegative !!
Answer:
300 kg
Explanation:
The give parameters obtained from a similar question are;
The mass of oseltamivir per capsule = 75 mg
The mass of oseltamivir required, <em>M</em>, is given as follows;
M = The mass of oseltamivir per capsule × The mass taken per person per day × 5 days × The number of people in the city
M = 0.75 mg/capsule × 2 capsule/(day·person) × 5 days × 400,000 people
M = 300,000,000 mg = 300 kg
1.) Convert grams of glucose to moles of glucose:25.5g gluc. * (1 mol/180g gluc.) = 1.41E-1 mol gluc. Note. Molar mass gluc. = 180g/mol
2.) Convert grams of solvent to kilograms of solvent:398 g H2O * (1kg H2O/1000g H2O) = 0.398 kg H2O
3.) Determine molality (moles solute/kilogram solvent) of solux:1.41E-1 mol gluc./0.398 kg H2O = 3.5427E-1 mol/kg
4.) Employ Freezing Point Depression equation and determine the freezing point of the solux:
ΔT = i Kf mΔT= ? (°C)Kf = 1.86 (°C kg mol¯1)m = 3.5427E-1 (mol/kg)i = (assumed negligible)
ΔΤ = (1.86)(3.5427E-1)ΔT = 6.589Ε-1°C
5.) ΔT = 6.589Ε-1°C
25.5g gluc. * (1 mol/180g gluc.) = equal 0.14166, not 1.41E-1 mol glucose
Answer:
Molybdenum
Explanation:
Molybdenum is a chemical element with the symbol Mo and an atomic number of 42. This implies a total of 42 electrons in its orbital.
The atomic weight of Mo is 95.94g/mol.
Using the sublevel notation system, the electrons can be filled into the orbitals as shown below:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d⁴
The ending configuration of this element is therefore 4d⁴