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sladkih [1.3K]
3 years ago
8

When the end of earth's axis is tilted toward the sun, what season will we exprience in north america?

Physics
2 answers:
denis-greek [22]3 years ago
7 0
The north will Experience winter
Angelina_Jolie [31]3 years ago
6 0
When the North End of the axis is tilted toward the Sun North America has summer. When the south end of the axis is tilted toward the sun North America has winter.
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EMERGENCY!! Doing my Physics homework now and I need help on this one please - all information provided, I'd be very VERY gratef
IrinaK [193]

(a) The vertical motion is accelerated by gravity. The horizontal component is constant (neglecting air resistance, if this is not a projectile motion, the horizontal component would also be accelerated)

(b) Vertical:

v_y = 30\sin 40^\circ = 19.3\frac{m}{s}

Horizontal:

v_x = 30\frac{m}{s}\cos 40^\circ = 23.0 \frac{m}{s}

(c) Use the kinematic equation for distance. Calculate only the vertical component (horizontal is irrelevant):

s_y = -\frac{1}{2}gt^2 +vt\,,\,\,\,s_y=0\\0 = -\frac{1}{2}gt^2 +vt\\\frac{1}{2}gt =v\\t = \frac{2v}{g}= \frac{2\cdot30\sin 40^\circ\frac{m}{s}}{9.8\frac{m}{s^2}}=3.9s

The ball will be in the air for about 3.9 s.

(d) The range is the horizontal distance traveled. We know the ball is in the air for 3.9s and it moves with a horizontal velocity of 23 m/s. So:

s_x = 23\frac{m}{s}\cdot 3.9 s = 89.7m

The range is 89.7 meters.

6 0
3 years ago
The normal force acts ________________________ to the surface and the friction force act _______________ to the surface.
Agata [3.3K]
The first one is perpendicular and second one is opposite
5 0
4 years ago
A harmonic wave is traveling along a rope. The oscillator that generates the wave completes 40.0 vibrations in 22.3 s. A given c
Dmitrij [34]

Answer:

Explanation:

frequency of vibration

n = 40 / 22.3 per second.

= 1.794 per second

velocity of wave v = 369 / 13.5 cm / s

= 27.33 cm / s

wavelength = velocity / frequency

= 27.33 / 1.794

= 15.23 cm

8 0
3 years ago
A 0.03 kg golf ball is hit off the tee at a speed of 34 m/s. The golf club was in contact with the ball for 0.003 s. What is the
Liula [17]

Answer:

The average force on ball by the golf club is 340 N.

Explanation:

Given that,

Mass of the golf ball, m = 0.03 kg

Initial speed of the ball, u = 0

Final speed of the ball, v = 34 m/s

Time of contact, \Delta t=0.003\ s

We need to find the average force on ball by the golf club. We know that the rate of change of momentum is equal to the net external force applied such that :

F=\dfrac{\Delta p}{\Delta t}\\\\F=\dfrac{mv-mu}{\Delta t}\\\\F=\dfrac{mv}{\Delta t}\\\\F=\dfrac{0.03\ kg\times 34\ m/s}{0.003\ s}\\\\F=340\ N

So, the average force on ball by the golf club is 340 N.

4 0
4 years ago
Thiết bị nào sau đây không phải là nguồn điện
kumpel [21]

Thiết bị không phải nguồn điện:

Đáp án D

7 0
3 years ago
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