The normal force acts ________________________ to the surface and the friction force act _______________ to the surface.
1 answer:
You might be interested in
a) 30.0 cm
For any mirror, the radius of curvature is twice the focal length:
r = 2f
where
r is the radius of curvature
f is the focal length
For the mirror in this problem, we have
r = 60.0 cm is the radius of curvature
Therefore, solving the equation above for f, we find its focal length:
b) 90 cm
The mirror equation is:
where
s' is the distance of the image from the mirror
f is the focal length
s is the distance of the object from the mirror
For the situation in the problem, we have
f = +30.0 cm is the focal length (positive for a concave mirror)
s = 45.0 cm is the object distance from the mirror
Solving the formula for s', we find
c) -2
The magnification of the mirror is given by
where in this problem we have
s' = 90 cm is the image distance
s = 45.0 cm is the object distance
Solving the equation, we find:
So, the magnification is -2.
d) -12.0 cm
The magnification can also be rewritten as
where
y' is the height of the image
y is the heigth of the object
In this problem, we know
y = 6.0 cm is the height of the object
M = -2 is the magnification
Solving the equation for y', we find
and the negative sign means that the image is inverted.
Part e and f are exactly identical as part b) and c).