With a pulley system, a force of only 50 lb can lift a 500-lb weight. What is the mechanical advantage if this system is 100% ef
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First we need to find the acceleration of the skier on the rough patch of snow.
We are only concerned with the horizontal direction, since the skier is moving in this direction, so we can neglect forces that do not act in this direction. So we have only one horizontal force acting on the skier: the frictional force,
. For Newton's second law, the resultant of the forces acting on the skier must be equal to ma (mass per acceleration), so we can write:
Where the negative sign is due to the fact the friction is directed against the motion of the skier.
Simplifying and solving, we find the value of the acceleration:
Now we can use the following relationship to find the distance covered by the skier before stopping, S:
where
is the final speed of the skier and 
is the initial speed. Substituting numbers, we find:
We are only concerned with the horizontal direction, since the skier is moving in this direction, so we can neglect forces that do not act in this direction. So we have only one horizontal force acting on the skier: the frictional force,
Where the negative sign is due to the fact the friction is directed against the motion of the skier.
Simplifying and solving, we find the value of the acceleration:
Now we can use the following relationship to find the distance covered by the skier before stopping, S:
where
The frictional force while the mass is sliding will be 46.2 N.
<h3>What is friction force?</h3>
Opposition forces on the surface cause heat loss during the motion of an object known as the friction force.
Given data:
m(mass)= 10.0-kg
Θ (Inclination angle)=25.0o
Coefficient of sliding friction,=0.520
Coefficient of static friction,
The friction force, F=?
Resolve the force in the inclined plane;
Hence, the frictional force while the mass is sliding will be 46.2 N.
To know more about friction force refer to the link;
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