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2 years ago

A person is standing on a raft; their

Physics

2 answers:

klemol [59]2 years ago

5 0

Answer:

the volume displaced by the raft = 0.233 m3

Explanation:

correct for Acellus

krok68 [10]2 years ago

3 0

Answer:

The volume of water displaced by the raft is 0.233 m³

Explanation:

The question relates to Archimedes' principle which states that the buoyant force experienced by an object immersed in a fluid is equal to the weight of (the force of gravity on) the displaced fluid

The given parameters are;

The combined mass of the person and the raft, m = 233 kg

The liquid on which the raft is located = Water

The density of water, $\rho _{water}$ = 1000 kg/m³

Weight = Mass, m × g

Where;

m = The mass of the object

g = The acceleration due to gravity = 9.8 m/s²

Given that the raft is on the surface of the water (floating), the buoyant force is equal to the combined weight of the person and the raft = 233 kg

The combined weight of the person and the raft, $W_{combined}$ = 233 kg × 9.8 m/s² = 2,283.4 N

Therefore;

The buoyant force = 2,283.4 N = The weight of the water displaced

The mass of the water displaced, $m_{water}$ , = 2,283.4 N/(9.8 m/s²) = 233 kg

Density = Mass/Volume

The volume of water displaced by the raft = The mass of the water displaced/(The density of the water) = 233 kg/(1,000 kg/m³) = 0.233 m³.

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Serga [27]

Answer:

Warming signs before fad diet includes:

1. When a special type of diet is recommended for weight loss.

2. When quick weight loss is promised instead of advice on the need to exercise, eat healthy foods including fruits and vegetables, and adopt a good feeding behavior.

3. Promises rapid weight loss in a short period of time.

After taking the fad diet the following might be experienced:

1. Constipation.

2. Weakness and fatigue.

3. More accumulation of fats in the body in the long run after a short term normal BMI (Body mass index).

4. Lower metabolic rates over time.

Explanation:

weight loss is a practice adopted by people for various reasons ranging from the desire to stay healthy to, ability to pursue a career that requires a good Body Mass Index. For instance, A BMI (Body mass index) which is equal to a person's weight (kg) / (height(m))^2 of 30 and higher is considered obese.

Fad diet which may give a temporary result of weight loss is not considered totally healthy as it doesn't capture the need to eat a healthy balanced diet instead focuses on more routine consumption of a particular kind of diet.

A healthy weight loss plan captures the need to exercise, reduce body fats while eating healthy. Eating fruits, vegetables are also encouraged.

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3 years ago

What is the electric field strength inside the capacitor after insulating handles are used to pull the electrodes away from each

Bezzdna [24]

This question apparently comes after an EARLIER one,
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4 years ago

A spring with a spring constant of 95 n/m is compressed a distance of 0.45 m from its relaxed position. by how much does the spr

shusha [124]

A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs.
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3 years ago

Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton

pishuonlain [190]

Hello!

Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton force is applied to it.

Data:

Hooke represented mathematically his theory with the equation:

F = K * Δx

On what:

F (elastic force) = 2 N

K (elastic constant) = 4 N/cm

Δx (deformation or elongation of the elastic medium or distance from a spring) = ?

Solving:

$F = K * \Delta{x}$

$2\:N = 4\:N/cm*\Delta{x}$

$4\:N/cm*\Delta{x} = 2\:N$

$\Delta{x} = \dfrac{2\:\diagup\!\!\!\!\!N}{4\:\diagup\!\!\!\!\!N/cm}$

simplify by 2

$\Delta{x} = \dfrac{2}{4}\frac{\div2}{\div2}$

$\boxed{\boxed{\Delta{x} = \dfrac{1}{2}\:cm}}\Longleftarrow(distance)\end{array}}\qquad\checkmark$

Answer:

B.) 1/2 cm

_______________________

I Hope this helps, greetings ... Dexteright02! =)

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3 years ago

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Salsk061 [2.6K]

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