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2 years ago

A covalent bond in which electrons are shared unequally is

1 answer:

7 0

Covalent bonds = sharing of electrons between two atoms of the same elements or elements close to each other on the periodic table. Usually they are metals sometimes non-metals. In polar bonds electrons are shared unequally. Non polar bonds share electrons equally.

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Part 1. Determine the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm. Show your work.

zaharov [31]

If a sample of gas is a 0.622-gram, volume of 2.4 L at 287 K and 0.850 atm. Then the molar mass of the gas is 7.18 g/mol

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases.

An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given :

V = 2.4 L = 0.0024

P = 86126.25 Pa

T = 287 K

m = 0.622

R = 8.314

The ideal gas equation is given below.

n = PV/RT

n = 86126.25 x 0.0024 / 8.314 x 287

n = 0.622 / molar mass (n = Avogardos number)

Molar mass = 7.18 g

Hence, the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm is 7.18 g

More about the ideal gas equation link is given below.

brainly.com/question/4147359

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4 0

1 year ago

Proteins are also known as enzymes.<br> True or false

julia-pushkina [17]

Answer:

True

Explanation:

3 0

2 years ago

Read 2 more answers

A solution contains 90 mL of methanol, 18 mL of propanol, and 2 mL of diethyl ether. Which is the solvent in this solution?

otez555 [7]

Answer:

Methanol

Explanation:

5 0

2 years ago

Determine the number of grams of C4H10 that are required to completely react to produce 8.70 mol of CO2 according to the followi

Nitella [24]

Answer:

126.4 g of $C_{4}H_{10}$ are required

Explanation:

Balanced reaction: $2C_{4}H_{10}+13O_{2}\rightarrow 8CO_{2}+10H_{2}O$

According to balanced reaction-

8 moles of $CO_{2}$ are produced from 2 moles of $C_{4}H_{10}$

So, 8.70 moles of $CO_{2}$ are produced from $(\frac{2}{8}\times 8.70)$ moles of $C_{4}H_{10}$ or 2.175 moles of $C_{4}H_{10}$

Molar mass of $C_{4}H_{10}$ = 58.12 g/mol

So, mass of $C_{4}H_{10}$ required = $(2.175\times 58.12)g$ = 126.4 g

Hence 126.4 g of $C_{4}H_{10}$ are required

5 0

2 years ago

Calculate the pH of mixing 24 mL of 1M acetic acid with 76 mL of 1M sodium acetate. For the purpose of this calculation, assume

FromTheMoon [43]

Answer:

pH = 5.24

Explanation:

Mixture of acetic acid with acetate ion is a buffer (Mixture of a weak acid with its conjugate base). The pH of a buffer can be determined using Henderson-Hasselbalch equation:

pH = pKa + log₁₀ [A⁻] / [HA]

<em>Where pKa is -log Ka = 4.74; [A⁻] is the concentration of conjugate base (Acetate ion) and [HA] is molar concentration of the weak acid.</em>

Concentration of the acetic acid in the 100mL≡0.1L (76mL + 24mL) solution is:

[HA] = 0.024L ₓ (1mol / L) / 0.1L = 0.24M

[A⁻] = 0.076L ₓ (1mol / L) / 0.1L = 0.76M

Replacing in H-H equation:

pH = 4.74 + log₁₀ [0.76M] / [0.24M]

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7 0

3 years ago