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Murrr4er [49]
3 years ago
13

A covalent bond in which electrons are shared unequally is

Chemistry
1 answer:
tekilochka [14]3 years ago
7 0
Covalent bonds = sharing of electrons between two atoms of the same elements or elements close to each other on the periodic table. Usually they are metals sometimes non-metals. In polar bonds electrons are shared unequally. Non polar bonds share electrons equally.


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Who is generally credited with developing the process of using heat?
galina1969 [7]

Answer:

Robert Boyle

Explanation:

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6 0
2 years ago
How many moles of HCl are present in 4.7 L of a 4.23 M HCl solution?
REY [17]

Hey There!

Volume = 4.7 L

Molarity = 4.23 M

Therefore:

n = M *V

n = 4.23 * 4.7

n = 19.881 moles of HCl

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6 0
3 years ago
Which source would be the most reliable to validate a claim?
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Answer:

In general, print publications with authors and listed sources tend to be reliable because they provide sources which readers can verify. Likewise, Web postings with a .gov (posted by the United States government) are both current and reliable.

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4 0
3 years ago
CaBr + KOH – Ca(OH), + KBr (balance first) What mass, in grams, of
neonofarm [45]

Answer:

129.73 g of CaBr₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

CaBr₂ + 2KOH –> Ca(OH)₂ + 2KBr

Next, we shall determine the mass of CaBr₂ that reacted and the mass of Ca(OH)₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of CaBr₂ = 40 + (80×2)

= 40 + 160

= 200 g/mol

Mass of CaBr₂ from the balanced equation = 1 × 200 = 200 g

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Mass of Ca(OH)₂ from the balanced equation = 1 × 74 = 74 g

SUMMARY :

From the balanced equation above,

200 g of CaBr₂ reacted to produce 74 g of Ca(OH)₂.

Finally, we shall determine the mass of CaBr₂ that react when 48 g of Ca(OH)₂ were produced. This can be obtained as follow:

From the balanced equation above,

200 g of CaBr₂ reacted to produce 74 g of Ca(OH)₂.

Therefore, Xg of CaBr₂ will react to produce 48 g of Ca(OH)₂ i.e

Xg of CaBr₂ = (200 × 48)/74

Xg of CaBr₂ = 129.73 g

Thus, 129.73 g of CaBr₂ were consumed.

6 0
3 years ago
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VARVARA [1.3K]

Answer:

Explanation:88

6 0
3 years ago
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