Answer:
There are 0.1 moles of solute in 250 mL of 0.4 M solution.
Explanation:
First, recognize that the molar concentration tells you how many moles of the solute are present in one liter of solution. In a 0.4 M solution, there are 0.4 moles of solute in every liter of solution. You can determine the number of moles of solute in 250 mL of the solution using dimensional analysis.
250
ml . 1L/1000 L . 0.4mol / 1L
Units of liters and milliliters cancel, leaving you with a final answer in units of moles, at 0.1 mol.
Answer:
792.72g/L
Explanation:
density formula
density = mass/volume in L
so the density of acetone = 43.6/0.055
792.72g/L
Y=2x-6
Domain is (2,6) and the range is (-2,-18)
Answer:
12
Explanation:
The coefficient of the CO2 shows the amount of CO2 needed in the reaction so to react with 11 water, 12 molecules of carbon dioxide is needed.
When amino acids are linked together, they form a peptide bond. When it joins two amino acids, it forms a dipeptide bond. When a long chain of amino acids are joined by peptide bonds, it becomes a protein. As shown in the picture, it loses H-OH molecules.
So, it will appear in the product side as a H₂O molecule.
