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WITCHER [35]
3 years ago
8

How many grams of acetic anhydride are needed to react with 6.43 g of salicylic acid?

Chemistry
1 answer:
horsena [70]3 years ago
4 0

Here's your answer :)

C7H6O3 (Salicylic acid) + C4H6O3 (Ethanoic anhydride) => C9H8O4 (Aspirin) + C2H4O2 (Acetic acid)

3.54 g / 138.12 g·C7H6O3 mol−1 = 0.0256 moles C7H6O3.  

From eqn, 1 mole C7H6O3 reacts with 1 mole C4H6O3 so 0.0256 moles C4H6O3 reacted.  

Mass acetic anhydride needed = 0.0256 mol * 102.0886 g mol-1 = 2.61 g (to 3 sig fig).

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