How many grams of acetic anhydride are needed to react with 6.43 g of salicylic acid?
1 answer:
You might be interested in
Answer:
6,97x10⁻³ gallons
Explanation:
pH is defined as:
pH = -log [H⁺]
Thus, you need to have, in the end:
10⁻⁷ = [H⁺]
And you have, in the first:
= [H⁺]
The volume of swimming pool is:
700'000 galllons × = 2649787 L
Thus, the moles of H⁺ in the first and in the end are:
First:
× 2649787L = 1,24x10⁻³ moles
End:
× 2649787L = 0,265 moles
Thus, the moles of H⁺ you need to add are:
0,265 - 1,24x10⁻³ = <em>0,26376 moles</em>
These moles comes from 10M HCl, thus, the volume in gallons you need to add are:
=
<em>6,97x10⁻³ gallons</em>
<em></em>
I hope it helps!
Answer:
kp= 3.1 x 10^(-2)
Explanation:
To solve this problem we have to write down the reaction and use the ICE table for pressures:
2SO2 + O2 ⇄ 2SO3
Initial 3.4 atm 1.3 atm 0 atm
Change -2x - x + 2x
Equilibrium 3.4 - 2x 1.3 -x 0.52 atm
In order to know the x value:
2x = 0.52
x=(0.52)/2= 0.26
2SO2 + O2 ⇄ 2SO3
Equilibrium 3.4 - 0.52 1.3 - 0.26 0.52 atm
Equilibrium 2.88 atm 1.04 atm 0.52 atm
with the partial pressure in the equilibrium, we can obtain Kp.