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WITCHER [35]
3 years ago
8

How many grams of acetic anhydride are needed to react with 6.43 g of salicylic acid?

Chemistry
1 answer:
horsena [70]3 years ago
4 0

Here's your answer :)

C7H6O3 (Salicylic acid) + C4H6O3 (Ethanoic anhydride) => C9H8O4 (Aspirin) + C2H4O2 (Acetic acid)

3.54 g / 138.12 g·C7H6O3 mol−1 = 0.0256 moles C7H6O3.  

From eqn, 1 mole C7H6O3 reacts with 1 mole C4H6O3 so 0.0256 moles C4H6O3 reacted.  

Mass acetic anhydride needed = 0.0256 mol * 102.0886 g mol-1 = 2.61 g (to 3 sig fig).

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One benefit of using ph instead of molar concentrations is that since molarity is a rate of “ moles per liter" ,  Molarity (M) is used to measure the concentration of hydrogen ions in a solution, which is used with pH applications. ... The H+ is the molarity number, which shows the concentration of hydrogen ions in the solution.

8 0
3 years ago
Calculate the ratio of the velocity of helium atoms to the velocity of neon atoms at the same temperature.
o-na [289]

Answer:

vHe / vNe = 2.24

Explanation:

To obtain the velocity of an ideal gas you must use the formula:

v = √3RT / √M

Where R is gas constant (8.314 kgm²/s²molK); T is temperature and M is molar mass of the gas (4x10⁻³kg/mol for helium and 20,18x10⁻³ kg/mol for neon). Thus:

vHe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol

vNe = √3×8.314 kgm²/s²molK×T / √20.18x10⁻³kg/mol

The ratio is:

vHe / vNe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol / √3×8.314 kgm²/s²molK×T / √20.18x10⁻³kg/mol

vHe / vNe = √20.18x10⁻³kg/mol / √4x10⁻³kg/mol

<em>vHe / vNe = 2.24</em>

<em />

I hope it helps!

8 0
3 years ago
Q: A 25.5 mL aliquot of HCl (aq) of unknown concentration was titrated with 0.113 M NaOH (aq). It took 51.2 mL of the base to re
blondinia [14]
M ( HCl ) = ?

V ( HCl ) = 25.5 mL in liters : 25.5 / 1000 => 0.0255 L

M ( NaOH ) = 0.113 M

V ( NaOH ) = 51.2 mL / 1000 => 0.0512 L

number of moles NaOH:

n = M x V

n = 0.113 x <span> 0.0512 => 0.0057856 moles of NaOH

mole ratio:

</span><span>HCl + NaOH = NaCl + H2O
</span><span>
1 mole HCl -------------- 1 mole NaOH
( moles HCl ) ----------- </span><span> 0.0057856 moles NaOH
</span>
(moles HCl ) = <span> 0.0057856 x 1 / 1
</span>
= <span> 0.0057856 moles of HCl
</span>
M ( HCl ) = n / V

M =  0.0057856 / <span>0.0255
</span>
= 0.227 M

Answer A

hope this helps!

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Which example is an exothermic reaction?
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Answer:

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