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3 years ago

What is a current?

Chemistry

1 answer:

Agata [3.3K]3 years ago

7 0

is C a flow of electrons

Explanation:

because yeah I think Soo :D I'm not smart but I tried UwU

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A warm ocean transfers heat to the air above it. Which type of heat transfer is this

Zigmanuir [339]

Answer:

Conduction

Explanation:

Because When air is in contact with the ocean it is at a different temperature than the seas surface

7 0

3 years ago

Read 2 more answers

. What is the mass, in grams, of a sample of 7.83 × 1024 atoms of helium (He)?

erica [24]

Moles He = 7.83 x 10^24 / 6.02 x 10^23 =13.0

<span>mass He = 13.0 mol x 4.00 g/mol = 52.0 g</span>

6 0

3 years ago

Given these reactions, where X represents a generic metal or metalloid 1 ) H 2 ( g ) + 1 2 O 2 ( g ) ⟶ H 2 O ( g ) Δ H 1 = − 241

anygoal [31]

Answer : The enthalpy of the given reaction will be, -1048.6 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

The main reaction is:

$XCl_4(s)+2H_2O(l)\rightarrow XO_2(s)+4HCl(g)$ $\Delta H=?$

The intermediate balanced chemical reactions are:

(1) $H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(g)$ $\Delta H_1=-241.8kJ$

(2) $X(s)+2Cl_2(g)\rightarrow XCl_4(s)$ $\Delta H_2=+461.9kJ$

(3) $\frac{1}{2}H_2(g)+\frac{1}{2}Cl_2(g)\rightarrow HCl(g)$ $\Delta H_3=-92.3kJ$

(4) $X(s)+O_2(g)\rightarrow XO_2(s)$ $\Delta H_4=-789.1kJ$

(5) $H_2O(g)\rightarrow H_2O(l)$ $\Delta H_5=-44.0kJ$

Now reversing reaction 2, multiplying reaction 3 by 4, reversing reaction 1 and multiplying by 2, reversing reaction 5 and multiplying by 2 and then adding all the equations, we get :

(1) $2H_2O(g)\rightarrow 2H_2(g)+O_2(g)$ $\Delta H_1=2\times 241.8kJ=483.6kJ$

(2) $XCl_4(s)\rightarrow X(s)+2Cl_2(g)$ $\Delta H_2=-461.9kJ$

(3) $2H_2(g)+2Cl_2(g)\rightarrow 4HCl(g)$ $\Delta H_3=4\times -92.3kJ=-369.2kJ$

(4) $X(s)+O_2(g)\rightarrow XO_2(s)$ $\Delta H_4=-789.1kJ$

(5) $2H_2O(l)\rightarrow 2H_2O(g)$ $\Delta H_5=2\times 44.0kJ=88.0kJ$

The expression for enthalpy of main reaction will be:

$\Delta H=\Delta H_1+\Delta H_2+\Delta H_3+\Delta H_4+\Delta H_5$

$\Delta H=(483.6)+(-461.9)+(-369.2)+(-789.1)+(88.0)$

$\Delta H=-1048.6kJ$

Therefore, the enthalpy of the given reaction will be, -1048.6 kJ

4 0

3 years ago

Why is it better to give the actual speed of an object rather than to simply say it moved fast or it moved slowly

DIA [1.3K]

Specificity. It’s really loose to say that something is fast, since speed can be scalarly linked and relative. I could say that both a car on the highway is fast, but so is the speed of light. The actual speed of something helps to do away with the arbitrary nature of using “fast” and “slow”; however, we’re still at step one of the person who is receiving the information is unfamiliar with the scale that the actual speed is defined in.

3 0

3 years ago

What is the charge on the phosphorus atom in the polyatomic ion: PO4-3

oee [108]

Explanation:

The given radical is PO₄³⁻

To solve this problem, we need to understand what oxidation number entails.

The extent of the oxidation of each atom is expressed by the oxidation number.

Here are some rules for assigning them:

Elements in an uncombined state or elements that combines with one another, their oxidation number is zero.
The charge on an ion is its oxidation number
In an neutral compound, algebraic sum of all the oxidation numbers of all atoms is zero.
In a radical, the algebraic sum of all the oxidation numbers of the ions is equal to the charge on them.

Oxygen is known to have an oxidation number of -2;

PO₄³⁻

P + 4(-2) = -3

P -8 = -3

P = -3 + 8 = +5

The charge on phosphorus is +5

learn more:

Oxidation number brainly.com/question/2086855

#learnwithbrainly

3 0

3 years ago