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inessss [21]
3 years ago
12

What is a current?

Chemistry
1 answer:
Agata [3.3K]3 years ago
7 0

is C a flow of electrons

Explanation:

because yeah I think Soo :D I'm not smart but I tried UwU

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1. Express in conventional notation (no exponents) in the space provided within the
mina [271]

Answer:

a) 320: two significant figures.

b) 2,366: four significant figures.

c) 73.0: three significant figures.

d. 532.5: four significant figures.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to write each number by knowing we move the decimal places to the right as much as the exponent is, and also, we count every figure, even zeros, because they are to the right of the first nonzero digit:

a) 320: two significant figures because the rightmost zero is not preceded o followed by a decimal place.

b) 2,366: four significant figures.

c) 73.0: three significant figures, because the zero is followed by the decimal place.

d. 532.5: four significant figures.

Regards!

7 0
3 years ago
What’s IV DV and Controls
zavuch27 [327]

Answer:

Iv-Independent Variable the part that doesnt get affected by the Dependent. DV- Dependent Variable- the part that gets affected by the independent. Controls is what everything is gettong compared to

7 0
3 years ago
Its chemistry: isotopes, elements, due Wednesday thanks
bulgar [2K]

Answer:

Science, Science, Science!

Explanation:

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4 0
3 years ago
If a radioactive isotope has a half-life of 26.5 days, how many days does it take for a sample of the isotope to decrease by 35.
dangina [55]

Answer:

16.5 days

Explanation:

Given that:

Half life = 26.5 days

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac {ln\ 2}{t_{1/2}}

k=\frac {ln\ 2}{26.5}\ days^{-1}

The rate constant, k = 0.02616 days⁻¹

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given:

35.0 % is decomposed which means that 0.35 of [A_0] is decomposed. So,

\frac {[A_t]}{[A_0]} = 1 - 0.35 = 0.65

t = 7.8 min

\frac {[A_t]}{[A_0]}=e^{-k\times t}

0.65=e^{-0.02616\times t}

<u>t = 16.5 days.</u>

7 0
3 years ago
Enter a formula in cell b7 to calculate the average value of cells b2:b6
AVprozaik [17]
In order to calculate the average value of cells B2:B6, you need to enter the formula on cell B7, On the Home tab, in the Editing group, click the Sum (AutoSum) button arrow and select Average . (and press Enter). The answer in this question is On the Home tab, in the Editing group, click the Sum (AutoSum) button arrow and select Average . (and press Enter).
6 0
3 years ago
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