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Vlada [557]
3 years ago
6

On the diagram above, trace the path of a light ray through these materials

Chemistry
1 answer:
makvit [3.9K]3 years ago
4 0
We need the diagram to answer the question
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I haven't done any science assignments of the unit we are learning and I have no clue at all what it's all about...what is activ
IceJOKER [234]
Active Transport: Moves ions and molecules from lower to higher concentrations using energy.

Passive Transport: Move ions and molecules from high to lower concentrations without using energy.

The main difference is one uses ATP (energy) and the other does not.

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2 years ago
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What is the percentage of nitrogen, by mass, in calcium nitrate?.
SCORPION-xisa [38]

Answer:

<em>Nitrogen = 17.07%</em>

Explanation:

We are asked to calculate the percentage by mass of nitrogen in Ca(NO3)2.

The molar mass of calcium nitrate is 164,088 g/mol.

In this 164.088 g/mol there are 2 nitrogen atoms.

Molar mass of nitrogen = 14,0067 g/mol

% Nitrogen = molar mass of N/total molar mass of the compound

% Nitrogen =[(2 x 14.0067)/164.088]*100

% Nitrogen = 17.07%

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7 0
2 years ago
The mass number of 3 isotopes of magnesium are 24,25,26.what is the mass number of the most abundant isotope of magnesium.​
Anarel [89]

Answer:

24.4 amu or g/mole

Explanation:

24 x 0.790 = 19.0 amu

25 x 0.100 = 2.50 amu

26 x 0.110 = 2.86 amu

(Because of the 19.0, the sig figs go only to the 1/10 decimal place)

19.0 + 2.5 + 2.9 = 24.4 amu or g/mole

7 0
3 years ago
A chemist titrates of a hypochlorous acid solution with solution at . Calculate the pH at equivalence. The of hypochlorous acid
const2013 [10]

The question is incomplete, here is the complete question:

A chemist titrates 110.0 mL of a 0.2412 M hypochlorous acid (HCIO) solution with 0.0613 M NaOH solution at 25°C. Calculate the pH at equivalence. The pKa of hypochlorous acid is 7.50. Round your answer to 2 decimal places

<u>Answer:</u> The pH of the solution is 10.09

<u>Explanation:</u>

To calculate the volume of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HClO

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=0.2412M\\V_1=110.0mL\\n_2=1\\M_2=0.0613M\\V_2=?mL

Putting values in above equation, we get:

1\times 0.2412\times 110.0=1\times 0.0613\times V_2\\\\V_2=\frac{1\times 0.2412\times 110.0}{1\times 0.0613}=432.8mL

At equivalence, the number of moles of acid is equal to the number of moles of base. Also, the moles of salt which is NaClO will also be the same.

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}     .....(1)

  • <u>For HClO:</u>

Molarity of HClO solution = 0.2412 M

Volume of solution = 110.0 mL

Putting values in equation 1, we get:

0.2412M=\frac{\text{Moles of HClO}\times 1000}{110}\\\\\text{Moles of HClO}=\frac{(0.2412\times 110)}{1000}=0.026532mol

  • <u>For NaClO:</u>

Moles of NaClO = 0.026532 moles

Volume of solution = [432.8 + 110] mL = 542.8 mL

Putting values in above equation, we get:

\text{Molarity of NaClO}=\frac{0.026532\times 1000}{542.8}=0.0489M

To calculate the pH of the solution, we use the equation:

pH=7+\frac{1}{2}[pK_a+\log C]

where,

pK_a = negative logarithm of weak acid which is hypochlorous acid = 7.50

C = concentration of the salt = 0.0489 M

Putting values in above equation, we get:

pH=7+\frac{1}{2}[7.50+\log (0.0489)]\\\\pH=7+3.09=10.09

Hence, the pH of the solution is 10.09

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3 years ago
Pls pls I need help to solve this questions
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1) • Solubility is the ability of a substance to be dissolved especially in water
• Unit; mg/L (milligrams per liter)

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3 years ago
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