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1 year ago

Use Hess's law to calculate AG° rxn using the following information.

Chemistry

1 answer:

PIT_PIT [208]1 year ago

3 0

Answer:

AG rxn=+394.4 kJ

Explanation:

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How does your pattern of breathing change when you exercise and then rest ?

Paladinen [302]

Your pattern of breathing increases, making it faster than usual, when you're exercising because you're pushing your body to work harder and speeding up your heart rate making you tired.

When you're resting your breathing pattern should be steady and normal since you aren't doing anything that requires lots of body work or something that would make you out of breath.

Hope this helps,

Davinia.

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3 years ago

2. If Ben ran for 15 minutes and went 120 meters, how fast did he run?

jeka57 [31]

Answer:

8m/min

Explanation:

120 m / 15 min = 8 meters per min

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2 years ago

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A gas has a volume of 590 mL at temperature of -55.0 C. What volume will the gas occupy at 30.0 C show your work

DENIUS [597]

Data:
$V_{initial} = 590\:mL$
$T_{initial} = -55.0^0C$
converting to Kelvin
TK = TC + 273
TK = -55.0 + 273 → TK = 218.0 → $T_{initial} = 218.0\:K$
$V_{final} = ? (in\:milliliters)$
$T_{final} = 30.0^0C$
TK = TC + 273
TK = 30.0 + 273 → TK = 303.0 → $T_{final} = 303.0\:K$

By the first Law of Charles and Gay-Lussac, we have:
$\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }$

Solving:
$\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }$
$\frac{ 590 }{ 218.0 } = \frac{ V_{f} }{ 303.0 }$
Product of extremes equals product of means:
$218.0* V_{f} = 590*303.0$
$218.0 V_{f} = 178770$
$V_{f} = \frac{178770}{218.0}$
$\boxed{\boxed{V_{f} \approx 820.04\:mL}}\end{array}}\qquad\quad\checkmark$

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3 years ago

1. Chlorobenzene, C6H5C1, is used in the production of chemicals such as aspirin

Natalka [10]

C6H6(l) + 6 Cl2(g) = C6Cl6(s) + 6 HCl(g)

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2 years ago

For the following reaction, find the value of Q and predict the direction of change, given that a 1L flask initially contains 2

Tresset [83]

Answer:

C) Q < K, reaction will make more products

Explanation:

1/8 S8(s) + 3 F2(g) ↔ SF6(g)

∴ Kc = 0.425 = [ SF6 ] / [ F2 ]³

∴ Q = [ SF6 ] / [ F2 ]³

∴ [ SF6 ] = 2 mol/L

∴ [ F2 ] = 2 mol/L

⇒ Q = ( 2 ) / ( 2³)

⇒ Q = 0.25

⇒ Q < K, reaction will make more products

5 0

2 years ago