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Leokris [45]
1 year ago
13

Use Hess's law to calculate AG° rxn using the following information.

Chemistry
1 answer:
PIT_PIT [208]1 year ago
3 0

Answer:

AG rxn=+394.4 kJ

Explanation:

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Calculate the gravitional force in between two object of mass 25kg and 20kg if distance between them is 5m?
astraxan [27]

Answer:

Explanation:The equation for this is F = -GmM/R^2 where the minus sign says the force is attractive m is 10 kg, M is 20 kg and R is 5 meters. If you crunch the numbers you get an answer of:

7 0
3 years ago
When we looked at assigning the electrons in nitrogen to sites in the 2s and 2p orbitals, we used the 2s anti-bonding site. Whic
AveGali [126]

Answer:

B) Although this site is not desirable for making a bond between atoms, it is a good site in the sense that the electrons can be close to the nucleus.  

Explanation:

An antibonding orbital points away from the nuclei, with a node between them, so the electrons are not held close to the nuclei. The orbital is not desirable for bonding.

The diagram below shows a σ*1s molecular orbital, but a σ*2s orbital has a similar shape.

A) is true. The σ*1s orbital has the lowest energy.

C) is true. Any orbital can accommodate at most one electron pair.

D) is may be true. Orbital energy decreases as atomic number increases, so the orbital energy of an N₂ σ*2s molecule may be close to that of a sulfur atom's 2s orbital.

6 0
4 years ago
Four pennies are heated to different temperatures. At which temperature
bonufazy [111]

Answer:

c

Explanation:

4 0
3 years ago
Read 2 more answers
What mass of carbon dioxide is produced from the complete combustion of 6.00×10−3 g of methane?
Crazy boy [7]

The answer for the following problem is explained below.

  • <u><em>Therefore 16.5 × 10^-3 grams of carbon dioxide is produced from the complete combustion.</em></u>

Explanation:

Given:

mass of methane = 6.00 × 10^-3 grams

CH_{4} + O_{2} → CO_{2} + H_{2}O

Firstly balance the following equation:

Before balancing the equation:

CH_{4} + O_{2} → CO_{2}  + H_{2} O

After balancing the equation:

CH_{4}  + 2O_{2} → CO_{2} + 2 H_{2} O

where;

CH_{4}  represents methane molecule

O_{2} represents oxygen molecule

CO_{2}  represents carbon dioxide molecule

H_{2}O  represents water molecule

 

       CH_{4} +2 O_{2} → CO_{2} + 2H_{2}O

        16  grams of methane       →        44 grams of carbon dioxide

        6 × 10^-3 grams of methane →          ?

                 = \frac{44*6.00*10^{-3} }{16}

          = 16.5 × 10^-3 grams of carbon dioxide is produced from the complete combustion.

<u><em>Therefore 16.5 × 10^-3 grams of carbon dioxide is produced from the complete combustion.</em></u>

5 0
3 years ago
Suppose you have a mixture of solid mg(oh)2 and baso4, how do you separate the mixture
Step2247 [10]
This separation technique is a 4-step procedure. First, add H₂SO₄ to the solution. Because of common ion effect, BaSO₄ will not react, only Mg(OH)₂.

Mg(OH)₂ + H₂SO₄ → MgSO₄ + 2 H₂O

The aqueous solution will now contain MgSO₄ and BaSO₄. Unlike BaSO₄, MgSO₄ is soluble in water. So, you filter out the solution. You can set aside the BaSO₄ on the filter paper. To retrieve Mg(OH)₂, add NaOH.

MgSO₄ + 2 NaOH = Mg(OH)₂ + Na₂SO₄

Na₂SO₄ is soluble in water, while Mg(OH)₂ is not. Filter this solution again. The Mg(OH)₂ is retrieved in solid form on the filter paper.
5 0
3 years ago
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