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VLD [36.1K]
2 years ago
13

A 250 mL sample of gas is collected over water at 35°C and at a total pressure of 735 mm Hg. If the vapor pressure of water at 3

5°C is 42.2 torr, what is the volume of the gas sample at standard pressure?
Chemistry
1 answer:
ELEN [110]2 years ago
4 0

Answer:

The volume of the gas sample at standard pressure is <u>819.5ml</u>

Explanation:

Solution Given:

let volume be V and temperature be T and pressure be P.

V_1=250ml

V_2=?

P_{total}=735 mmhg

1 torr= 1 mmhg

42.2 torr=42.2 mmhg

so,

P_{water}=42.2mmhg

T_1=35°C=35+273=308 K

Now

firstly we need to find the pressure due to gas along by subtracting the vapor pressure of water.

P_{gas}=P_{total}-P_{water}

=735-42.2=692.8 mmhg

Now

By using combined gas law equation:

\frac{P_1*V_1}{T_1} =\frac{P_2*V_2}{T_2}

V_2=\frac{P_1*}{P_2}*\frac{T_2}{T_1} *V_1

V_2=\frac{P_gas}{P_2}*\frac{T_2}{T_1} *V_1

Here P_2 \:and\: T_2 are standard pressure and temperature respectively.

we have

P_2=750mmhg \:and\: T_2=273K

Substituting value, we get

V_2=\frac{692.8}{750}*\frac{273}{308} *250

V_2= 819.51 ml

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A lab team places 0.250g of an unknown solid acid in an Erlenmeyer flask. They neutralize the solid acid with 15.0ml of 0.210 M
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since mole ratio of acid : base is 1 : 1, so;

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Answer:

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Explanation:

Data Given:

mass of total sample = 14.2 g

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percent composition of Hg =

percent composition of O =

Solution:

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As this compound only have two components that is oxygen and mercury

So

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now to find mass of oxygen we have to subtract mass of mercury from total mass of sample

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% composition = component mass / total mass of sample x 100. . . .(1)

For % composition of mercury Hg

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Put values in equation 1

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