Answer: 25.8 g of
will be produced from the decomposition of 73.4 g of
Explanation:
To calculate the moles :

The balanced chemical reaction is:
According to stoichiometry :
2 moles of
produce = 3 moles of 
Thus 0.242 moles of will produce=
of 
Mass of
= 
Thus 25.8 g of
will be produced from the decomposition of 73.4 g of
Answer:
where is the drawing? I can't help if I can't see it sorry
Answer:
0.2 M.
Explanation:
- For the acid-base neutralization, we have the role:
The no. of millimoles of acid is equal to that of the base at the neutralization.
<em>∴ (XMV) KOH = (XMV) H₂SO₄.</em>
X is the no. of reproducible H⁺ (for acid) or OH⁻ (for base),
M is the molarity.
V is the volume.
X = 1, M = 0.5 M, V = 38.74 mL.
X = 2, M = ??? M, V = 50.0 mL.
∴ M of H₂SO₄ = (XMV) KOH/(XV) H₂SO₄ = (1)(0.5 M)(38.74 mL)/(2)(50.0 mL) = 0.1937 M ≅ 0.2 M.
I believe the correct response is the first option.