Answer:
a) N
b) m/s
Explanation:
a)
= radius of the orbit = 0.522 x 10⁻¹⁰ m
= magnitude of charge on each proton and electron = 1.6 x 10⁻¹⁹ C
Using coulomb's law , magnitude of electric force on the particle is given as
N
b)
= mass of electron = 9.1 x 10⁻³¹ kg
= speed of electron = ?
Centripetal force is being provided by the electric force, hence
Centripetal force = electric force
m/s
The force responsible for slowing it’s: Friction force
The suns gravity pulls on the planets and keeps them in place. Its gravitational pull puts them in orbit around the sun
Answer:
D) 30.6J
Explanation:
Because:
gravitational potential energy=mass×gravitational field strength×height
1.3kg×9.8m/2squared×2.4m
= 30.6J
Answer:
The number of photons per second that strike the given area is 2.668 x 10⁸ photons/second
Explanation:
Given;
intensity of the sunlight, I = 2.00 kJ·s−1·m^−2
area of incident, A = 5.2 cm² = 5.2 x 10⁻⁴ m²
Energy of incident photons per second on the given area;
E = IA
E = (2000)( 5.2 x 10⁻⁴)
E = 1.04 J/s
Energy of a photon is given is by;
The number of photons per second that strike the given area is;
Therefore, the number of photons per second that strike the given area is 2.668 x 10⁸ photons/second