There is a total of 6 half lives that need to take place.
ONE HALF LIFE = 200
TWO HALF LIFES = 100
THREE HALF LIFES = 50
FOUR HALF LIFES = 25
FIVE HALF LIFES = 12.5
SIX HALF LIFES = 6.25
The answer is 6.25g
Answer:
<h3>13,976.23Joules</h3>
Explanation:
Workdone by the rope is expressed using the formula;
W = Fd sin(theta)
F is the tension in the rope = 180
d is the displacement = 300m
theta is the angle of inclination = 15°
Substitute the given parameters into the formula;
W = 180(300)sin15
W = 54000sin 15
W = 13,976.23
Hence the workdone by the rope is 13,976.23Joules
Answer:
conductor, insulator, resists, semiconductor, 3 and 5 group
Explanation:
Answer:
dilution = 2.5*10^6
Explanation:
Given:
- Number of colonies N = 100 cfu
- The Volume of cells = 25*10^7 cells / ml
Find:
the final dilution
Solution:
- The expression relating the the colonies forming unit with cells//volume is given as:
Bacteria/ml = cfu*dilution
dilution = Volumetric cells/ cfu
dilution = 25*10^7 / 100
dilution = 2.5*10^6
