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3 years ago

Ethylene glycol has a density of 1.11g/cm3. What is the mass in grams of 387ml of ethylene glycol?

1 answer:

4 0

Density is defined as the mass per unit volume.
formula is as follows
$density = \frac{mass}{volume}$
we have been given the density and volume so we need to find the mass of ethylene glycol
if we rearrange the equation making mass the subject
mass = density x volume
density = 1.11 g/cm³
this means that 1 cm³ of solution has a mass of 1.11 g
since mL = cm³
therefore 387 cm³ of solution has a mass of 1.11 g/cm³ x 387 cm³ = 429.6 g
mass of ethylene glycol is 429.6 g

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Gaseous hydrogen iodide is placed in a closed container at 425∘C, where it partially decomposes to hydrogen and iodine: 2HI(g)⇌H

murzikaleks [220]

Answer:

0.0184

Explanation:

Let's consider the following reaction at equilibrium.

2 HI(g) ⇌ H₂(g) + I₂(g)

The concentration equilibrium constant (Kc) is equal to the product of the concentration of the products raised to their stoichiometric coefficients divided by the product of the concentration of the reactants raised to their stoichiometric coefficients.

Kc = [H₂] × [I₂] / [HI]²

Kc = (4.78 × 10⁻⁴) × (4.78 × 10⁻⁴) / (3.52 × 10⁻³)²

Kc = 0.0184

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3 years ago

What is the amount of energy for a photon that has a 125 cm wavelength

Lera25 [3.4K]

Answer:

1.59 x 10⁻²⁵ J.

Explanation:

The energy of a photon is calculated Planck - Einstein's equation:

E = h ν , where

E is the energy of the photon,

h is Planck's constant (h = 6.626 x 10 ⁻³⁴ J.s)

ν is the frequency of the photon

There is a relation between the frequency (ν ) and wave length (λ).

λ.ν = c,

where c is the speed of light in vacuum (c = 3 .0 x 10 ⁸ m/s).

λ = 125 cm = 1.25 m.

Now, E = h.c/λ.

∴ E = h.c/λ = (6.626 x 10 ⁻³⁴ J.s) (3 .0 x 10 ⁸ m/s) / (1.25 m) = 1.59 x 10⁻²⁵ J.

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3 years ago

Examples of a pure substances

DiKsa [7]

Answer:

Explanation:

Examples of pure substances include tin, sulfur, diamond, water, pure sugar (sucrose), table salt (sodium chloride) and baking soda (sodium bicarbonate). Crystals, in general, are pure substances. Tin, sulfur, and diamond are examples of pure substances that are chemical elements.

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2 years ago

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Find the volume of 20g of H₂ at STP

ANEK [815]

Answer:224

Explanation:

We should answer it with Stoichiometry

We say: 20 g H2× (1 mol/ 2g)× ( 22.4 lit/ 1 mol) = 224

Means: we have 20 grams and every 2g H2, equals to 1 mol of it and every 1 mol of H2, equals to 22.4 lit( because of STP)

hope you got this:)

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3 years ago

Another example of a parasitic

sasho [114]

Answer:a leech

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