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Arisa [49]
3 years ago
8

Ethylene glycol has a density of 1.11g/cm3. What is the mass in grams of 387ml of ethylene glycol?

Chemistry
1 answer:
FromTheMoon [43]3 years ago
4 0
Density is defined as the mass per unit volume. 
formula is as follows
density =  \frac{mass}{volume}
we have been given the density and volume so we need to find the mass of ethylene glycol
if we rearrange the equation making mass the subject
mass = density x volume
density = 1.11 g/cm³
this means that 1 cm³ of solution has a mass of 1.11 g
since mL = cm³
therefore 387 cm³ of solution has a mass of 1.11 g/cm³ x 387 cm³ = 429.6 g
mass of ethylene glycol is 429.6 g
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Write the empirical formula for at least four ionic compounds that could be formed from the following ions:
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The empirical formula of compounds formed from the given ions are as follows:

  • Pb⁴⁺ = PbO₂
  • NH₄⁺ = NH₄Cl
  • CrO₄²⁻ = Na₂CrO₄
  • SO₄²⁻ = K₂SO₄

<h3>What is the empirical formula of a compound?</h3>

The empirical formula of a compound is the simplest formula of the compound showing the simplest ratios in which elements in the compound combine.

The empirical formula of compounds formed from the given ions are as follows:

  • Pb⁴⁺ = PbO₂
  • NH₄⁺ = NH₄Cl
  • CrO₄²⁻ = Na₂CrO₄
  • SO₄²⁻ = K₂SO₄

In conclusion, the empirical formula is the simplest formula of a compound.

Learn more about empirical formula at: brainly.com/question/1581269

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Which term refers to the smallest particle of a compound with all the properties of that compound?
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molecule. The smallest part of a compound is the molecule. A molecule retains all the properties of that compound.

Explanation:

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Explain what a scientific theory is, and what is necessary to make a theory strong and well supported?
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Glucose (C6H12O6) can be fermented to yield ethanol (CH3CH2OH) and carbon dioxide (CO2). C6H12O6⟶2CH3CH2OH+2CO2 The molar mass o
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Answer:

The % yield is 74.45 %

Explanation:

<u>Step 1:</u> The balanced equation

C6H12O6⟶2CH3CH2OH+2CO2

<u>Step 2</u>: Data given

Molar mass glucose = 180.15 g/mol

Molar mass of ethanol = 46.08 g/mol

Molar mass of carbon dioxide = 44.01 g/mol

Mass of glucose = 61.5 grams

Mass of ethanol = 23.4 grams

<u>Step 3:</u> Calculate moles of glucose

Moles glucose = Mass glucose  / Molar mass of glucose

Moles glucose = 61.5 grams / 180.15 g/mol

Moles glucose = 0.341 moles

<u>Step 4:</u> Calculate moles of ethanol

1 mole of glucose consumed, produces 2 moles of ethanol and 2 moles of CO2

0.341 moles of glucose, will produce 2*0.341 = 0.682 moles of ethanol

<u>Step 5:</u> Calculate mass of ethanol

Mass ethanol = moles ethanol * Molar mass ethanol

Mass ethanol = 0.682 moles * 46.08 g/mol

Mass ethanol = 31.43 grams = theoretical mass

<u>Step 6:</u> Calculate % yield

% yield = actual mass / theoretical mass

% yield = (23.4 grams / 31.43 grams) * 100%

% yield = 74.45 %

The % yield is 74.45 %

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3 years ago
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