Ethylene glycol has a density of 1.11g/cm3. What is the mass in grams of 387ml of ethylene glycol?
1 answer:
Density is defined as the mass per unit volume.
formula is as follows
we have been given the density and volume so we need to find the mass of ethylene glycol
if we rearrange the equation making mass the subject
mass = density x volume
density = 1.11 g/cm³
this means that 1 cm³ of solution has a mass of 1.11 g
since mL = cm³
therefore 387 cm³ of solution has a mass of 1.11 g/cm³ x 387 cm³ = 429.6 g
mass of ethylene glycol is 429.6 g
formula is as follows
we have been given the density and volume so we need to find the mass of ethylene glycol
if we rearrange the equation making mass the subject
mass = density x volume
density = 1.11 g/cm³
this means that 1 cm³ of solution has a mass of 1.11 g
since mL = cm³
therefore 387 cm³ of solution has a mass of 1.11 g/cm³ x 387 cm³ = 429.6 g
mass of ethylene glycol is 429.6 g
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Answer : The excess reactant in the combustion of methane in opem atmosphere is molecule.
Solution : Given,
Mass of methane = 23 g
Molar mass of methane = 16.04 g/mole
The Net balanced chemical reaction for combustion of methane is,
First we have to calculate the moles of methane.
=
= 1.434 moles
From the above chemical reaction, we conclude that
1 mole of methane react with the 2 moles of oxygen
and 1.434 moles of methane react to give moles of oxygen
The Moles of oxygen = 2.868 moles
Now we conclude that the moles of oxygen are more than the moles of methane.
Therefore, the excess reactant in the combustion of methane in open atmosphere is molecule.