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Gekata [30.6K]
3 years ago
8

What are the correct coefficients when this chemical equation is balanced? * P4 + 02 P2O5

Chemistry
1 answer:
finlep [7]3 years ago
3 0

Answer:

What are the correct coefficients when this chemical equation is

balanced? *

P4 + 02 P2O5

<h2>1, 5, 2</h2>

Explanation:

For this reaction we have a combination reaction. Balancing Strategies: This combination reaction is a lot easier to balance and if you can get an even number of oxygen atoms on the reactants side of the equation.

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Suppose a large atom bonds with a small atom.  Will the properties of the new molecule be the same as the large atom, the small
Stels [109]
Everything will be the same except that the atoms will be together nothing changes!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1
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Which compound (s) has(have) a molecular ion at 117 and a peak at 1720 cm-1 in its IR spectrum?
LenaWriter [7]

Answer:

Ethyl Acetate with a chemical configuration of : CH3CO2CH2CH3

Explanation:

Ethyl Acetate has a density of 902 kg/m³, molar mass of 88.11 g/mol and posses a boiling point of 77.1 °C.

It is to be understood that ethyl acetate is the  ester of ethanol and it is mostly produced in mass production and most especially used in the production of domestic materials especially materials like glue, efostics and dissolving agent. This is a highly toxic and flammable substance. However colorless and possess a sweet smell, it can be highly poisonous when ingested.

3 0
4 years ago
Formaldehyde organic or inorganic
scZoUnD [109]
Formaldehyde is an organic compound.
8 0
4 years ago
A 1.2516 gram sample of a mixture of caco3 and na2so4 was analyzed by dissolving the sample and completely precipitating the ca
Dennis_Churaev [7]

Answer:

0.009725 moles of H2C2O4

0.009725 moles CaCO3

Mass percentage =  77.77%

Explanation:

<u>Step 1</u>: The balanced equation

2MnO4- +5C2H2O4+6H+ →2Mn2+ +10CO2+8H2O

We can see that for 2 moles of Mno4- consumed , there is 5 moles of C2H2O4 needed and 6 moles H+ to produce 2 moles Mn2+, 10 moles of CO2 and 8 moles of H2O

<u>Step 2</u>: Calculate moles of MnO4-

Molarity = Moles/volume

Moles of Mno4- = Molarity of MnO4- * Volume of Mno4-

Moles of Mno4- = 0.1092M * 35.62 *10^-3 L

Moles of MnO4- = 0.00389 moles

<u>Step 3</u>: Calculate moles of H2C2O4

Since there is needed 5 moles of C2H2O4 to consume 2 moles of MnO4-

then for 0.00389 moles of MnO4-, there is 5/2 *0.00389 = <u>0.009725 moles of H2C2O4</u>

<u />

<u>Step 4:</u> Calculate moles of CaCO3

moles of H2C2O4 = moles CaCO3, therefore, 0.009725 moles H2C2O4 = 0.009725 moles CaCO3

<u>Step 5</u>: Calculate mass of CaCO3

Molar mass of CaCO3 = 100.09 g/mole

Mass of CaCO3 = moles of CaCO3 * Molar mass of CaCO3

Mass of CaCO3 = 0.009725 moles * 100.09 g/mole = 0.9734 g

<u>Step 6</u>: Calculate percentage by weight of CaCO3

Mass of CaCO3 = 0.9734g

Mass of original sample = 1.2516g

Mass percentage = 0.9734/1.2516 *100% = 77.77%

6 0
4 years ago
What are the two species in highest concentration in a 0.1 M solution of lactic acid (CH3CH(OH)C00H), (Ka
rusak2 [61]

Answer:

1.4 × 10^-4.

Explanation:

C3H6O3 + H2O <======> C3H5O3^- + H3O^+ ------------------------------------------(1).

So, from the question above we are given the following parameters or data which is going to help in solving this particular Question/problem;

=>concentration of the solution of lactic acid (CH3CH(OH)C00H) = 0.1 M and pH = 2.44.

Therefore, the concentration of the hydrogen ion[H^+} can be determined from the pH formula given below;

pH = - log { H^+}.

2.44 = - log { H^+}.

Therefore, {H^+} = 0.0036 M.

From the equation (1) given above, we have that the ratio for the equilibrium reaction is 1 : 1 : 1 :1. Therefore, molarity of C3H5O3^- = 0.0036 M and the molarity of C3H6O3 =( 0.1 - 0.0036 M) = 0.0964 M at equilibrium.

Hence, ka = {C3H5O3^-} { H3O^+} /{C3H6O3} = ( 0.0036 M)^2 /(0.0964 M) = 1.4 × 10^-4.

6 0
3 years ago
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