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3 years ago

5/12-3/20 use the least common multiple as the denominator

1 answer:

6 0

The common multiple of 12 and 20 is 60.
You've got to multiply the first one by 5 and the second by 3.
5*5= 25
This therefore becomes 25/60
The second becomes 3*3= 9
This becomes 9/60
As you're subtracting, you only subtract the numerators.
25-9= 16
Therefore, the answer is 16/60 which can be simplified to 4/10 or 2/5
Hope this helps :)

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An internet site asks its membersmembers to call in their opinion regarding their web searching habits. Which type of sampling i

SOVA2 [1]

Answer: E. Convenience

Step-by-step explanation:

A convenience sampling is a method of sampling whose structure is based on accessibility to the researcher .

Given : An internet site asks its members to call in their opinion regarding their web searching habits.

Here the internet site is working according to its accessibility .

Hence, this is a type of convenience sampling .

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3 years ago

hillary is cycling across montana taking a 845 mile course . the first week she covered.320 miles. the second week she traveled

Blababa [14]

Answer:

175 miles

Step-by-step explanation:

Hillary has travelled

320 + 350 = 670 miles

in the first two weeks.

Therefore, Hillary starts with 670 miles and needs to add a certain number of miles "x" to get 845 in total.

670 + x = 845

And if we subtract 670 from both sides:

x = 845 - 670 = 175

175 miles

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3 years ago

Let X1, . . . ,Xn be an i.i.d. random sample from a N(0, 1) population. Define Y1 = 1 n n X i=1 Xi , Y2 = 1 n n X i=1 |Xi| . Cal

nalin [4]

For each $1\le i\le n$ , $E[X_i]=0$ , so that

$\displaystyle E[Y_1]=E\left[\frac1n\sum_{i=1}^nX_i\right]=\frac1n\sum_{i=1}^nE[X_i]=0$

Meanwhile,

$\displaystyle E[Y_2]=\frac1n\sum_{i=1}^nE[|X_i|]$

Each of the $X_i$ have PDF

$f_{X_i}(x)=\dfrac1{\sqrt{2\pi}}e^{-x^2/2}$

for $x\in\Bbb R$ . From this we get

$E[|X_i|]=\displaystyle\frac1{\sqrt{2\pi}}\int_{-\infty}^\infty|x|e^{-x^2/2}\,\mathrm dx=\sqrt{\frac2\pi}\int_0^\infty xe^{-x^2/2}\,\mathrm dx=\sqrt{\frac2\pi}$

$\implies E[Y_2]=n\sqrt{\dfrac2\pi}$

8 0

3 years ago

Solve. High school pre-cal

Oliga [24]

Answer:

<em>Answer: Quadrant 4</em>

Step-by-step explanation:

<u>Graph of Functions </u>

Let's analyze the function

$\displaystyle y=\frac{x^2+3x}{x+1}$

To better understand the following analysis, we'll factor y

$\displaystyle y=\frac{x(x+3)}{x+1}$

For y to have points in the first quadrant, at least one positive value of x must produce one positive value of y. It's evident that any x greater than 0 will do. For example, x=1 will make y to be positive in the numerator and in the denominator, so it's positive

For y to have points in the second quadrant, at least one negative value of x must produce one positive value of y. We need two of the factors that are negative. It can be seen that x=-2 will make y as positive, going through the second quadrant.

For the third quadrant, we have to find at least one value of x who produces a negative value of y. We only need to pick a value of x that makes one or all the factors be negative. For example, x=-4 produces a negative value of y, so it goes through the third quadrant

Finally, the fourth quadrant is never reached by any branch because no positive value of x can produce a negative value of y.

Answer: Quadrant 4

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3 years ago

In the diagram, how many circles are there for each square?

notsponge [240]

The answer would be be B)2. The ratio of circles to squares is 2 to 1

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3 years ago

Read 2 more answers