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Nutka1998 [239]
3 years ago
10

Which of the following is the correct formula for copper (I) sulfate trihydrate? CuSO4 · 3H2O

Chemistry
2 answers:
Ahat [919]3 years ago
8 0
<h3>Answer:</h3>

                   Cu₂SO₄ · 3 H₂O

<h3>Explanation:</h3>

                         First of all we should be interested in the oxidation number carried out by Copper atom because it can exist both in +1 and +2 state. Hence, as shown in name<em> i.e. </em>(I), it shows that copper is having +1 oxidation state.

                          Secondly, we should be interested in the charge carried out by sulfate ion, as it is conjugate base of sulfuric acid so, it must contain a charge of -2.

                           Therefore, to neutralize -2 charge of SO₄²⁻ ion we have to add two Cu⁺¹ ions hence,

                                             Cu₂SO₄

Furthermore, the number of water molecules are three as the word tri- specifies three.

                                        Cu₂SO₄ . 3 H₂O

<h3>Remember:</h3>

                    In naming ionic compounds the positive part is named first followed by negative ion.

PilotLPTM [1.2K]3 years ago
6 0
It is either the 3rd answer or the 4th answer. Both are correct ways to write hydrates, but I was taught the 4th way. Just make sure this answer matches the format of the examples your teacher gave you.
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Pick two(2) solid metal blocks with varying temperatures ( i.e. one solid block is hot and the other solid block is cold )

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