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Nutka1998 [239]
3 years ago
10

Which of the following is the correct formula for copper (I) sulfate trihydrate? CuSO4 · 3H2O

Chemistry
2 answers:
Ahat [919]3 years ago
8 0
<h3>Answer:</h3>

                   Cu₂SO₄ · 3 H₂O

<h3>Explanation:</h3>

                         First of all we should be interested in the oxidation number carried out by Copper atom because it can exist both in +1 and +2 state. Hence, as shown in name<em> i.e. </em>(I), it shows that copper is having +1 oxidation state.

                          Secondly, we should be interested in the charge carried out by sulfate ion, as it is conjugate base of sulfuric acid so, it must contain a charge of -2.

                           Therefore, to neutralize -2 charge of SO₄²⁻ ion we have to add two Cu⁺¹ ions hence,

                                             Cu₂SO₄

Furthermore, the number of water molecules are three as the word tri- specifies three.

                                        Cu₂SO₄ . 3 H₂O

<h3>Remember:</h3>

                    In naming ionic compounds the positive part is named first followed by negative ion.

PilotLPTM [1.2K]3 years ago
6 0
It is either the 3rd answer or the 4th answer. Both are correct ways to write hydrates, but I was taught the 4th way. Just make sure this answer matches the format of the examples your teacher gave you.
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Which kind of plate boundary created the Mid-Atlantic Ridge or the chain of volcanoes underneath Atlantic Ocean?
Natali [406]

Answer:

Divergent plate boundary

Explanation:

7 0
3 years ago
An unbalanced equation is shown. In this reaction, 200.0 g of FeS2 is burned in 100.0 g of oxygen, and 55.00 g of Fe2O3 is produ
Crazy boy [7]
<span>4FeS2 + 11O2 = 2Fe2O3 + 8SO2</span>

Percent yield is calculated as the actual yield divided by the theoretical yield multiplied by 100.

Actual yield = 55 g ( 1 mol / 159.69 g ) = 0.34 mol Fe2O3

To find for the theoretical yield, we first determine the limiting reactant.

100 g O2 ( 1 mol / 32 g) = 3.13 mol O2
200 g FeS2 (1 mol / 119.98g) = 1.67 mol FeS2

Therefore, the limiting reactant is O2.

Theoretical yield = 3.13 mol O2 ( 2 mol Fe2O3 / 11 mol O2 ) = 0.57 mol Fe2O3

Percent yield = (0.34 mol / 0.57 mol) x 100 = 59.74%
3 0
3 years ago
Given following electron configurations, 1s22s22p63s23p64s23d104p65s24d9 and 1s22s22p63s23p64s23d104p65s14d10.
marusya05 [52]

Explanations:- Part 1: We could count the total number of electrons by looking at the electron configurations. Both of these electrons configurations have 47 electrons. If we look at the periodic table then 47 is the atomic number of silver. So, the name of the element is silver and its represented as Ag.

Part 2: As per the rule, Completely filled and half filled orbitals are more stable. First electron configuration has 9 electrons in 4d and we know that d is more stable if it has 5 electrons(half filled) or it has 10 electrons(full filled).

For stability reasons, one of the electron from 5s goes to 4d and for this reason the second electron configuration is found most often in nature for silver.

Few other examples are Cr and Cu.

8 0
3 years ago
Why Are aquifers important to our freshwater supply? 5TH GRADE ANSWER c:
ANEK [815]

Explanation:

Aquifers are porous and permeable formations that stores ground water. The ground water system is made up of mostly fresh water.

  • An aquifer acts as a reserve for ground water in the environment.
  • By passing through different formations, water that recharges them are purified.
  • This makes them fresh and mostly free from salt intrusion

An aquifer is able to store this fresh water and it is is good prospect for sourcing ground water.

4 0
3 years ago
the value of ksp for pbcl2 is 1.6. what is the lowest concentration of Cl- that would be needed to begin precipitation of PbCl2
deff fn [24]

Answer:

The minimum concentration of Cl⁻ that produces precipitation is 12.6M

Explanation:

The Ksp of PbCl₂ is expressed as:

PbCl₂(s) → Pb²⁺(aq) + 2Cl⁻(aq)

The Ksp is:

Ksp = 1.6 = [Pb²⁺] [Cl⁻]²

When Ksp = [Pb²⁺] [Cl⁻]² the solution begind precipiration.

A 0.010M Pb(NO₃)₂ is 0.010M Pb²⁺, thus:

1.6 = [0.010M] [Cl⁻]²

160 = [Cl⁻]²

12.6M =  [Cl⁻]

<h3>The minimum concentration of Cl⁻ that produces precipitation is 12.6M</h3>
7 0
3 years ago
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