<h3>Answer:</h3>
Cu₂SO₄ · 3 H₂O
<h3>Explanation:</h3>
First of all we should be interested in the oxidation number carried out by Copper atom because it can exist both in +1 and +2 state. Hence, as shown in name<em> i.e. </em>(I), it shows that copper is having +1 oxidation state.
Secondly, we should be interested in the charge carried out by sulfate ion, as it is conjugate base of sulfuric acid so, it must contain a charge of -2.
Therefore, to neutralize -2 charge of SO₄²⁻ ion we have to add two Cu⁺¹ ions hence,
Cu₂SO₄
Furthermore, the number of water molecules are three as the word tri- specifies three.
Cu₂SO₄ . 3 H₂O
<h3>Remember:</h3>
In naming ionic compounds the positive part is named first followed by negative ion.