Answer:
92.9%
Explanation:
You have been given the actual yield of the reaction. First, you need to find the theoretical yield of the reaction. To do this, you need to (1) convert grams Fe₂O₃ to moles Fe₂O₃ (via molar mass from periodic table values), then (2) convert moles Fe₂O₃ to moles Fe (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Fe to grams Fe (via molar mass).
Once you have found the theoretical yield, you need to use the percent yield equation to calculate the final answer. This number should have 3 sig figs to match the given values.
<u>(Step 1)</u>
Molar Mass (Fe₂O₃): 2(55.845 g/mol) + 3(15.998 g/mol)
Molar Mass (Fe₂O₃): 159.684 g/mol
1 Fe₂O₃(s) + 3 CO(g) ---> 2 Fe(s) + 3 CO₂(g)
Molar Mass (Fe): 55.845 g/mol
50.0 g Fe₂O₃ 1 mole 2 moles Fe 55.845 g
-------------------- x ------------------ x --------------------- x ---------------- = 35.0 g Fe
159.684 g 1 mole Fe₂O₃ 1 mole
<u>(Step 2)</u>
Actual Yield
Percent Yield = --------------------------- x 100%
Theoretical Yield
32.5 g Fe
Percent Yield = ---------------------- x 100% = 92.9%
35.0 g Fe
Answer:
B. pour the reagent into a small beaker before using it
Explanation:
Let's explore all the mentioned practice
A. Leftover reagents should not be discarded in the sink but discarded according to the disposal method present in the safety data sheet (SDS) of the chemical.
B. Reagents should be poured in a clean beaker for use to avoid contamination in the original reagent bottle
C. This is not a good practice, as the plastic pipet tends to contain some impurity in its tip.
D. This is also a bad practice. Firstly, a reagent should be taken according to the need. If there is leftover, it should be discarded as it most probably contains contamination in it
I think it is true. The formation reaction always means that the product substance is made directly and all by the elements of the reactants. And standard means under 25℃ and one atmosphere.
The balanced chemical reaction is:
<span>2 I2 + KIO3 + 6 HCl ---------> 5 ICl + KCl + 3 H2O
</span>
We are given the amount of the product to be produced from the reaction. This will be the starting point of our calculations.
28.6 g ICl (1 mol / 162.35 g ICl ) ( 2 mol I2 / 5 mol ICl ) ( 253.81 g I2 / 1 mol I2 ) = 17.88 g I2
Answer:
honestly
idek what all that is
if your this far into what ever this is
id quit and just live life
Explanation:
