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hichkok12 [17]
3 years ago
15

5. How are compounds different from mixtures?

Chemistry
1 answer:
Vlad [161]3 years ago
6 0

Answer:

Compounds cant be separated while mixtures can

Explanation:

Compounds have a chemical bond that cant be split while mixtures dont and could be split

You might be interested in
I wanted known how many of the reaction below is energy released
Tema [17]

Answer:

2

Explanation:

In two reactions energy is released.

1) C₆H₁₂O₆ + 6O₂    →    6H₂O + 6CO₂ + heat

It is cellular respiration reaction.It involves the breakdown of glucose molecule in the presence of oxygen to yield large amount of energy. Water and carbon dioxide are also produced as a byproduct.

Glucose + oxygen → carbon dioxide + water + 38ATP

2) 2H₂ + O₂   →    2H₂O  ΔH = -486 kj/mol

The given reaction is formation of water. In this reaction oxygen and hydrogen react to form water and 486 kj/mol is also released.

The reaction in which heat is released is called exothermic reaction.

Exothermic reaction:

The type of reactions in which energy is released are called exothermic reactions.

In this type of reaction energy needed to break the bonds are less than the energy released during the bond formation.

For example:

Chemical equation:

C + O₂   →  CO₂

ΔH = -393 Kj/mol

it can be written as,

C + O₂   →  CO₂ + 393 Kj/mol

Endothermic reactions:

The type of reactions in which energy is absorbed are called endothermic reactions.

In this type of reaction energy needed to break the bond are higher than the energy released during bond formation.

For example:

C + H₂O   →  CO  + H₂

ΔH = +131 kj/mol

it can be written as,

C +  H₂O  + 131 kj/mol  →  CO  + H₂

5 0
3 years ago
Five kilograms of liquid carbon tetrachloride undergo a mechanically reversible, isobaric change of state at 1 bar during which
Drupady [299]

Answer:

Explanation:

From the information given:

Mass of carbon tetrachloride = 5 kg

Pressure = 1 bar

The given density for carbon tetrachloride = 1590 kg/m³

The specific heat of carbon tetrachloride =  0.84 kJ/kg K

From the composition, the initial volume of carbon tetrachloride will be:= \dfrac{5 \ kg }{1590 \ kg/m^3}

= 0.0031 m³

Suppose \beta is independent of temperature while pressure is constant;

Then:

The change in volume can be expressed as:

\int ^{V_2}_{V_1} \dfrac{dV}{V} =\int ^{T_2}_{T_1} \beta dT

In ( \dfrac{V_2}{V_1})  = \beta (T_2-T_1)

V_2 = V_1 \times exp (\beta (T_2-T_1))

V_2 = 0.0031 \ m^3  \times exp  (1.2 \times 10^{-3} \times 20)

V_2 = 0.003175 \ m^3

However; the workdone = -PdV

W = -1.01 \times 10^5 \ Pa \times ( 0.003175 m^3 - 0.0031 \ m^3)

W = - 7.6 J

The heat energy Q = Δ h

Q = mC_p(T_2-T_1)

Q = 5 kg \times 0.84 \ kJ/kg^0 C \times 20

Q = 84 kJ

The internal energy is calculated by using the 1st law of thermodynamics; which can be expressed as;

ΔU = ΔQ + W

ΔU = 84 kJ + ( -7.6 × 10⁻³ kJ)

ΔU = 83.992 kJ

3 0
3 years ago
When 9.36 g sodium hydroxide is dissolved in enough water to make a total volume of 965 mL, what is the concentration of the res
SSSSS [86.1K]

Answer:

0.2425 M

Explanation:

Given mass = 9.36 g

Molar mass of NaOH = 39.997 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{9.36\ g}{39.997\ g/mol}

Moles\ of\ NaOH= 0.234\ mol

Given that:- Volume = 965 mL = 0.965 L ( 1 mL = 0.001 L )

So,

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.234\ mol}{0.965\ L}=0.2425\ M

5 0
4 years ago
Read 2 more answers
Look at the food pyramid below.
Alborosie

Answer:

1 - producer, 2 - primary consumer, 3 - secondary consumer, 4 - tertiary consumer

Explanation:

4 0
3 years ago
Read 2 more answers
I need help on 26, 28, 36-40
gtnhenbr [62]

26. a megagram = 10⁶ grams while a kilogram = 10³ grams, so the megagram is bigger

28. a mililiter = 10⁻³ liters while a microliter = 10⁻⁶ liters, so the mililiter is bigger

36.   1 meter is equal to 100 centimeters, so the decimal moves right 2 places

37. 1 micrometer is equal to 0.001 milimeters, so the decimal moves left 3 places

38. 1 centimeter is equal to 0.00001 kilometers, so the decimal moves left 5 places

39. 1 micrometer is equal to 10⁻¹² megameters, so the decimal moves left 12 places

40. 1 kilometer is equal to 100000 centimeters, so the decimal moves right 5 places

5 0
3 years ago
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