Question

A diver jumps up off a diving board with an initial velocity of 3.75m/s. What is their velocity when they reach the water 4.0m below?

Answer 1

Answer:
final velocity = 9.6157 m/sec

Explanation:
To solve this question, we will use one of the equations of motion which is:
v^2 = u^2 + 2as
where:
v is the final velocity that we want to get
u is the initial velocity = 3.75 m/sec
a is the acceleration due to gravity = 9.8 m/sec^2
s is the distance = 4 m

Substitute with the givens in the equation to get the final velocity as follows:
v^2 = u^2 + 2as
v^2 = (3.75)^2 + 2(9.8)(4)
v^2 = 92.4625
v = 9.6157 m/sec

Hope this helps :)