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3 years ago

9

You are traveling on the interstate highway at a speed of 65 mph. What is your speed in km/h? The conversion factor is: 1.0 mph=

1.6 km/h.

1 answer:

chubhunter [2.5K]3 years ago

6 0

You have to cross multiply. So set up the equation like 1.6/x = 1/65 then multiply x by 1 and 1.6 by 65. The answer is 104 km/h.

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How much total energy is dissipated in 10. seconds

noname [10]

Answer : Total energy dissipated is 10 J

Explanation :

It is given that,

Time. t = 10 s

Resistance of the resistors, R = 4-ohm

Current, I = 0.5 A

Power used is given by :

$P=\dfrac{E}{t}$

Where

E is the energy dissipated.

So, E = P t.............(1)

Since, $P=I^2R$

So equation (1) becomes :

$E=I^2Rt$

$E=(0.5\ A)^2\times 4\Omega \times 10\ s$

$E=10\ J$

So, the correct option is (3)

Hence, this is the required solution.

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An arrow is moving at 35 m/s and travels for 5 seconds. how far did the arrow travel?

pashok25 [27]

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2 years ago

The membrane that surrounds a certain type of living cell has a surface area of 4.3 x 10-9 m2 and a thickness of 1.1 x 10-8 m. A

Nadusha1986 [10]

Answer:

The charge resides on the outer surface = $1.245 \times 10^{-12}$ C

Explanation:

Surface area of cell $(A) = 4.3\times 10^{-9} m^{2}$

Separation between two plate $(d) = 1.1 \times 10^{-8} m$

Dielectric constant $(k) = 4.2$

Potential difference $(\Delta V) = 85.7 \times 10^{-3} V$

The capacitance of parallel plate capacitor in free space is given by,

$C = \frac{\epsilon_{o} A }{d}$

Where $\epsilon_{o} =$ permittivity of free space = $8.85 \times 10^{-12}$

The Capacitance of capacitor is increase by $k$ times when it placed in dielectric medium.

$C_{dielectric} = \frac{k \epsilon_{o} A }{d}$

And we know that, $C = \frac{Q}{ \Delta V}$

So charge on the outer surface is given by,

$Q = \frac{k \epsilon A \Delta V }{d}$

$Q = \frac{4.2 \times 4.3 \times 10^{-9} \times 8.85 \times 10^{-12} \times 85.7\times 10^{-3} }{1.1 \times 10^{-8} }$

$Q = 1.245 \times 10^{-12}$

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3 years ago

What is the wavelength of microwaves with a frequency of 3x10^10 Hz?

RUDIKE [14]

Answer:

0.01 m

Explanation:

Since the speed of light is 3.0×10^8 m/s

Use the equation,

Wavelength = speed ÷ frequency

Wavelength = 3.0×10^8 ÷ 3×10^10

Wavelength = 0.01m

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2 years ago

The average Intensity of the electromagnetic field due to sunlight at the surface of the earth is 1400 W/m^2. Calculate the maxi

Ann [662]

Answer:

1027 N/C

3.42 x 10⁻⁶ T

Explanation:

I = Intensity of electromagnetic field = 1400 W/m²

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I = (0.5) ε₀ E₀² c

1400 = (0.5) (8.85 x 10⁻¹²) (3 x 10⁸) E₀²

E₀ = 1027 N/C

B₀ = maximum value of magnetic field

using the equation

E₀ = B₀ c

1027 = B₀ (3 x 10⁸)

B₀ = 3.42 x 10⁻⁶ T

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2 years ago