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3 years ago

a car is moving with a constant speed of 20 meters per second.What total distance does the car travel in 2 minutes

Physics

1 answer:

N76 [4]3 years ago

8 0

There are 120 seconds in two minutes, so to find the answer, you multiply 20 x 120 to get 2400 meters.

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When a falling body is at distance above the surface which is 4 times the Earth radius what is the acceleration due to Earth gra

Hoochie [10]

Answer:

Explanation:

g = GM/R²

as gravity decreases by the inverse of the square of the distance, increasing the distance by 4 times will reduce gravity to 1/16 that at the surface

9.8 / 16 = 0.61 m/s²

8 0

3 years ago

What is the rate of photosynthesis?

Pepsi [2]

Answer:

photosynthesis is the process by which green plant manufacture their own food using sunlight from the sun , water and mineral salt from the soil

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3 years ago

Camouflage is to blend in with what

Elanso [62]

To blend in with your surroundings

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3 years ago

A ball is launched at an angle of 10 degrees from a 20 meter tall building with a speed of 4 m/s. How long is the ball in the ai

shutvik [7]

Answer:

d) None of the above

Explanation:

$v_{o}$ = inituial velocity of launch = 4 m/s

θ = angle of launch = 10 deg

Consider the motion along the vertical direction

$v_{oy}$ = initial velocity along vertical direction = 4 Sin10 = 0.695

m/s

$a_{y}$ = acceleration along the vertical direction = - 9.8 m/s²

y = vertical displacement = - 20 m

t = time of travel

using the equation

$y=v_{oy} t+(0.5)a_{y} t^{2}$

- 20 = (0.695) t + (0.5) (- 9.8) t²

t = 2.1 sec

consider the motion along the horizontal direction

x = horizontal displacement

$v_{ox}$ = initial velocity along horizontal direction = 4 Cos10 = 3.94 m/s

$a_{x}$ = acceleration along the horizontal direction = 0 m/s²

t = time of travel = 2.1 s

Using the kinematics equation

$x =v_{ox} t+(0.5)a_{x} t^{2}$

x = (3.94) (2.1) + (0.5) (0) (2.1)²

x = 8.3 m

Consider the motion along the vertical direction

$v_{oy}$ = initial velocity along vertical direction = 4 Sin10 = 0.695

m/s

$a_{y}$ = acceleration along the vertical direction = - 9.8 m/s²

$y_{o}$ =initial vertical position at the time of launch = 20 m

$y$ = vertical position at the maximum height = 20 m

$v_{fy}$ = final velocity along vertical direction at highest point = 0 m/s

using the equation

${v_{fy}}^{2}= {v_{oy}}^{2} + 2 a_{y}(y - y_{o})$

$0^{2}= 0.695^{2} + 2 (- 9.8)(y - 20)$

$y$ = 20.02 m

h = height above the starting height

h = $y$ - $y_{o}$

h = 20.02 - 20

h = 0.02 m

7 0

3 years ago

Water bubbles up through a hot spring at yellowstone national park. What method of heat transfer is this?

LuckyWell [14K]

I believe the answer is CONVECTION.

hope that helps!!!

4 0

3 years ago

Read 2 more answers