First solve the quadratic as you would an equation, so you will get two real zeroes p and q so that (x-p)(x-q)=0 is another way of expressing the quadratic. All quadratics can be represented graphically by a parabola, which could be inverted. When the x² coefficient is negative it’s inverted. If the coefficient of x² isn’t 1 or -1 divide the whole quadratic by the coefficient so that it takes the form x²+ax+b, where a and b are real fractions. The curve between the zeroes will be totally below the x axis for an upright parabola, and totally above for an inverted parabola. This fact is used for inequalities. An inequality will be <, ≤, > or ≥. This makes it easy to solve the inequality. If the position of the curve between the zeroes is below the axis then outside this interval it will be above, and vice versa. So we’ve defined three zones. x
q, and p
Answer:
What are we trying to figure out with this information??
P.S. I am not collecting the points, I will revise my answer once you fix the question!! :)
BD is 31 degrees because it is the same.
ADB is 90-31 because it is a right angle ( 59 degrees)
DEC is 180 - (31*2) because the 180 is of the trangle and the 31 is the same on the other side so times 2 then removed from 180
Use the distance formula.
Points S and W.
~3.6
Points S and T
~3.6
Points T and U
~3.1
Points U and V
~4
Points V and W
~3.3
Add all these together.
3.3 + 3.1 + 4 + 3.1 + 3.6
≈17
Answer:
the sum of the of the square of the opposite and adjacent does not equal the hypotenuse
