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Yuki888 [10]
3 years ago
5

If a substance has a half-life of 55.6 s, and if 230.0 g of the substance are present initially, how many grams will remain afte

r 10.0 minutes?
Chemistry
1 answer:
Assoli18 [71]3 years ago
6 0

Answer:

m=0.127g

Explanation:

Hello,

In this case, for a first-order reaction, we can firstly compute the rate constant from the given half-life:

k=\frac{ln(2)}{t_{1/2}} =\frac{ln(2)}{55.6s}=0.0125s^{-1}

In such a way, the integrated first-order law, allows us to compute the final mass of the substance once 10.0 minutes (600 seconds) have passed:

m=m_0*exp(-kt)=230.0g*exp(-0.0125s^{-1}*600s)\\\\m=0.127g

Best regards.

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