Answer:
u = 9,95x10⁻²⁷ kg
Explanation:
The reduced mass is defined as the effective inertial mass appearing in the two-body problem of Newtonian mechanics.
The formula is:
![u = \frac{m_{1}m_{2}}{m_{1} + m_{2}}](https://tex.z-dn.net/?f=u%20%3D%20%5Cfrac%7Bm_%7B1%7Dm_%7B2%7D%7D%7Bm_%7B1%7D%20%2B%20m_%7B2%7D%7D)
As the mass of the carbons is 1,99x10⁻²⁶ kg:
![u = \frac{1,99x10^{-26}kg1,99x10^{-26}kg}{1,99x10^{-26}kg + 1,99x10^{-26}kg}](https://tex.z-dn.net/?f=u%20%3D%20%5Cfrac%7B1%2C99x10%5E%7B-26%7Dkg1%2C99x10%5E%7B-26%7Dkg%7D%7B1%2C99x10%5E%7B-26%7Dkg%20%2B%201%2C99x10%5E%7B-26%7Dkg%7D)
<em>u = 9,95x10⁻²⁷ kg</em>
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I hope it helps!
Answer:
i) Buffer absorbs H^+ and OH^- ions preventing large changes in pH when small amounts of acid or base is added but when large amounts of acid or base is added there will be a change in pH
ii) absorption of liquid is related to a chemical reaction for a buffer system but it is not related a chemical reaction for a proton( H ) sponge.
Explanation:
<u>i) Buffer like a proton ( H ) sponge </u>
Buffer absorbs H^+ and OH^- ions preventing large changes in pH when small amounts of acid or base is added but when large amounts of acid or base is added there will be a change in pH
The pH of a Buffer follows the Henderson-Hasselbach model
pH = pKa + Log ([A-]/[HA])
when base is added
HA + OH^- -------> A- + H2O
when acid is added
A^- + H^+ ---------> HA
<u>ii) Buffer not like a proton ( H ) sponge</u>
absorption of liquid is related to a chemical reaction for a buffer system but it is not related a chemical reaction for a proton( H ) sponge.