A. cesium. bacause as the elements go down a group of the atoms, the sizes of the atom will increase . we know that tge tendency to lose an electron is based on the sizes of the atoms of group 1.
Answer is: b) decomposition.
Synthesis is reaction of two or more substances combining to make a more complex substance.
Decomposition is reaction where one substance is broken down into two or more simpler substances.
For example, balanced chemical reactio:
CaCO₃(s) → CaO(s) + CO₂(g).
Chemical decomposition is the separation of a single chemical compound (in this example calcium carbonate) into its two or more simpler compounds (in this example calcium oxide and carbon dioxide).
Combustion is reaction with oxygen.
Single Displacement is reaction where neutral element metal or nonmetal become an ion as it replaces another ion in a compound.
Double displacement reactions (more reactive metals displace metals with lower reactivity).
Answer:
The solution is not ideal.
The relative strengths of the solute-solvent interactions are greater compared to the solute-solute and solvent-solvent interactions
Explanation:
The total vapor pressure is the sum of the partial pressures of water and methanol, and they are calculated by the Raoult´s law equation:
Pₐ = Xₐ Pºₐ, where Pₐ is the partial pressure of component A
Xₐ is the molar fraction of A
P⁰ₐ is the pressure of pure A
So lets calculate the partial pressures of methanol and water and compare them with the given total vapor pressure of solution:
X H2O = 0.312 ⇒ X CH3OH = 1 - 0.312 = 0.688
PH2O = 0.312 x 55.3 torr = 17.3 torr
PCH3OH = 0.688 x 256 torr = 176.1 torr
Ptotal = PH2O + PCH3OH = 17.3 torr + 176.1 torr = 193.4 torr
This pressure is less than the experimental value of 211 torr. So the solution is not ideal. The relative strength of the solute-solvent interactions are greater than the solute-solute and solvent-solvent interactions.
The reason for this is the presence of hydrogen bonding between methanol and water.
Answer:
K(eq) = 15 (2 sig. figs)
Explanation:
Rxn: CO(g) + 2H₂(g) ⇄ CH₃OH(l)
C(eq): 0.150M 0.360M 0.282M
Keq = [CH₃OH(l)]/[CO(g)][H₂(g)]
= (0.282M)/(0.150M)(0.360M)²
= 14.50617284 (calc. ans.)
= 15 (2 sig. figs.)
