Answer:
option C
(4,4)
Step-by-step explanation:
Given in the question an inequality
y ≤ x² - 3x + 2
(1,1)
when x = 1
y ≤ 1² - 3 + 2
y ≤ 0
1 ≤ 0
Rejected as 1 is greater than 0
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(2,2)
when x = 2
y ≤ 2² - 3(2) + 2
y ≤ 0
2 ≤ 0
Rejected as 2 is grater than 0
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(4,4)
when x = 4
y ≤ 4² - 3(4) + 2
y ≤ 6
4 ≤ 6
Accepted as 4 is lesser than 6
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(3,3)
when x = 3
y ≤ 3² - 3(3) + 2
y ≤ 2
3 ≤ 2
Rejected as 3 is greater than 2
Answer:
1
Step-by-step explanation:
(1+sinx)/cosx
(1+sin0)/cos0
(1+0)/1
1/1
1
:. Lim x->0 =1
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Answer:
(B) -25/4
Step-by-step explanation:
-5/3 ÷ 4/15
Copy dot flip
-5/3 * 15/4
Rewriting for easier math
-5/4 * 15/3
-5/4 * 5
-25/4
See the picture attached with letters to better understand the problem
in the right triangle ABD
applying the Pythagoras theorem
8²=AD²+(x+4)²-----> AD²=64-(x+4)²------> equation 1
in the right triangle ADC
applying the Pythagoras theorem
12²=AD²+(2x+1)²-----> AD²=144-(2x+1)²------> equation 2
equate equation 1 and equation 2
64-(x+4)²=144-(2x+1)²-------> 64-[x²+8x+16]=144-[4x²+4x+1]
64-x²-8x-16=144-4x²-4x-1
4x²-x²-8x+4x=144-1-64+16
3x²-4x=95
3x²-4x-95=0
using a graph tool----> to resolve the second order equation
see the attached figure N 2
the solution is
x=6.33
the answer isx=6.33 units