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Shalnov [3]
3 years ago
7

Write the quadratic equation of the parabola that passes through (-2,5) and has a vertex of (1,-3)

Mathematics
1 answer:
guapka [62]3 years ago
6 0
-8/3x - 1/3 is the equation
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I need help :)<br> .....
qwelly [4]

Answer:D)

Step-by-step explanation:

5 0
3 years ago
A manufacturer is designing a flashlight. For the flashlight to emit a focused beam, the bulb needs to be on the central axis of
aalyn [17]
From the problem, the vertex = (0, 0) and the focus = (0, 3)
From the attached graphic, the equation can be expressed as:
(x -h)^2 = 4p (y -k)
where (h, k) are the (x, y) values of the vertex (0, 0)
The "p" value is the difference between the "y" value of the focus and the "y" value of the vertex.
p = 3 -0
p = 3
So, we form the equation
(x -0)^2 = 4 * 3 (y -0)
x^2 = 12y
To put this in proper quadratic equation form, we divide both sides by 12
y = x^2 / 12

Source:
http://www.1728.org/quadr4.htm




5 0
3 years ago
Yesterday, Marissa walked 1 1/2 miles from school to the ice
BigorU [14]

Answer:

2 1/6 miles

Step-by-step explanation:

1 1/2 miles + 2/3 miles = 2 1/6 miles

8 0
2 years ago
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