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olga2289 [7]
3 years ago
7

3. A cylinder of compressed gas has a pressure of 4.882 atm on one day. The next

Chemistry
1 answer:
Debora [2.8K]3 years ago
7 0

Answer:

PART A

Explanation:

3. A cylinder of compressed gas has a pressure of 4.882 atm on one day. The next

day, the same cylinder of gas has a pressure of 4.690 atm, and its temperature is

8°C. What was the temperature on the previous day in °C? Ans: 20°C.

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What are some sources of error associated with electroplating​
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<u>mass of reactants = mass of products</u> best represents the law of conservation of mass

Explanation:

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8 0
3 years ago
For the reaction of oxygen and nitrogen to form nitric oxide, consider the following thermodynamic data (Due to variations in th
CaHeK987 [17]

Answer:

a. 7278 K

b. 4.542 × 10⁻³¹

Explanation:

a.

Let´s consider the following reaction.

N₂(g) + O₂(g) ⇄ 2 NO(g)

The reaction is spontaneous when:

ΔG° < 0  [1]

Let's consider a second relation:

ΔG° = ΔH° - T × ΔS° [2]

Combining [1] and [2],

ΔH° - T × ΔS° < 0

ΔH° < T × ΔS°

T > ΔH°/ΔS°

T > (180.5 × 10³ J/mol)/(24.80 J/mol.K)

T >  7278 K

b.

First, we will calculate ΔG° at 25°C + 273.15 = 298 K

ΔG° = ΔH° - T × ΔS°

ΔG° = 180.5 kJ/mol - 298 K × 24.80 × 10⁻³ kJ/mol.K

ΔG° = 173.1 kJ/mol

We can calculate the equilibrium constant using the following expression.

ΔG° = - R × T × lnK

lnK = - ΔG° / R × T

lnK = - 173.1 × 10³ J/mol / (8.314 J/mol.K) × 298 K

K = 4.542 × 10⁻³¹

7 0
2 years ago
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