1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
krek1111 [17]
1 year ago
8

I got first part correct but dont know how to solve the other 2 problems

Physics
1 answer:
Vsevolod [243]1 year ago
5 0

To determine the amount of electrons in a given charge we need to remember that the charge of an electros is:

e=-1.602\times10^{-19}

coulombs.

Now, if we have a given amount of charge an we want to know how many electrons are in the charge we divide it by the charge in the electron. In this case we have:

\frac{-1650\times10^{-9}}{-1.602\times10^{-19}}=1.03\times10^{13}

Therefore we have:

1.03\times10^{13}\text{ electrons }

We know that for each step the worker collects -50nC, this is the same as collecting:

\frac{-50\times10^{-9}}{-1.602\times10^{\cdot19}}=3.12\times10^{11}\text{electrons}

electrons. Now, that we know this we divide the maximum amount of charge the component can take by the electrons in each step:

\frac{10^{12}}{3.12\times10^{-11}}=3.2

Threfore the worker can take 3 complete steps before touching the component

You might be interested in
A soft drink (mostly water) flows in a pipe at a beverage plant with a mass flow rate that would fill 220 0.355 - L cans per min
jekas [21]

Answer:

a)  1.301 kg/s

b) 0.001301 m³/s

c) V₁ = 6.505 m/s, V₂ = 1.626 m/s

d) 118.93 kPa

Explanation:

Given:

The number of cans  = 220

The volume of can, V = 0.355 L = 0.355 × 10⁻³ m³

time = 1 minute = 60 seconds

gauge pressure at point 2, P₂ = 152 kPa

b) Thus, the volume flow rate, Q = Volume/ time

Q = (220 × 0.355 × 10⁻³)/60 = 0.001301 m³/s

a) mass flow rate = Volume flow rate × density

since it is mostly water, thus density of the drink = 1000 kg/m³

thus,

mass flow rate = 0.001301 m³/s × 1000 kg/m³ = 1.301 kg/s

c) Given:

Cross section at point 1 = 2.0 cm² = 2 × 10 ⁻⁴ m²

Cross section at point 2 = 8.0 cm² = 8 × 10 ⁻⁴ m²

also,

Q = Area × Velocity

thus, for point 1

0.001301 m³/s = 2 × 10 ⁻⁴ m² × velocity at point 1 (V₁)

or

V₁ = 6.505 m/s

for point 2

0.001301 m³/s = 8 × 10 ⁻⁴ m² × velocity at point 1 (V₂)

or

V₂ = 1.626 m/s

d) Applying the Bernoulli's theorem between the points 1 and 2 we have

P_1+\rho gV_1 + \frac{\rho V_1^2}{2}=P_2+\rho gV_2 + \frac{\rho V_2^2}{2}

or

P_1=P_2+\rho\timesg(y_2-y_1)+\frac{\rho}{2}(V_2^2-V_1^2))

on substituting the values in the above equation, we get

P_1=152+1000\times 9.8(1.35)+\frac{1000}{2}(1.626^2-6.505^2))

it is given that point 1 is above point 2 thus, y₂ -y₁ is negative

or

P_1=118.93\ kPa

thus, gauge pressure at point 1 is 118.93 kPa

8 0
3 years ago
What is the international standard for measurement it is a modified version of the metric system
maxonik [38]

Answer:

SI system i think it is right

6 0
2 years ago
This chemical equation represents a ______________ reaction.
Ede4ka [16]

Answer:

you didnt put anything

Explanation:

7 0
3 years ago
Read 2 more answers
In the high jump, the kinetic energy of an athlete is transformed into gravitational potential energy without the aid of a pole.
Fiesta28 [93]

Answer:

6.0 m/s

Explanation:

According to the law of conservation of energy, the total mechanical energy (potential, PE, + kinetic, KE) of the athlete must be conserved.

Therefore, we can write:

KE_i+PE_i =KE_f+PE_f

or

\frac{1}{2}mu^2+0=\frac{1}{2}mv^2+mgh

where:

m is the mass of the athlete

u is the initial speed of the athlete (at the bottom)

0 is the initial potential energy of the athlete (at the bottom)

v = 0.80 m/s is the final speed of the athlete (at the top)

g=9.8 m/s^2 is the acceleration due to gravity

h = 1.80 m is the final height of the athlete (at the top)

Solving the equation for u, we find the initial speed at which the athlete must jump:

u=\sqrt{v^2+2gh}=\sqrt{0.80^2+2(9.8)(1.80)}=6.0 m/s

4 0
3 years ago
You have been called to testify as an expert witness in a trial involving a head-on collision. Car A weighs 1515 lb and was trav
serious [3.7K]

what was the speed limit, and it was 40 mph


6 0
3 years ago
Other questions:
  • the line on the position time graph show the velocites of different vehicles which line represents a vehicle moving at constant
    12·1 answer
  • In the living room of your house you would like to run a 360 W stereo, a 30 W computer, a 720 W laser light projector, and four
    11·1 answer
  • If a carbon atom was broken in half, would it still be carbon?
    7·1 answer
  • After a caterpillar eats a leaf, it can convert the chemical energy into _____ energy to help it build a cocoon.
    13·2 answers
  • PSYCHOLOGY propelling neural signals is a function of ______ neurotransmitters.
    9·1 answer
  • A crate which has a mass of m1 = 125kg is sitting on an icy surface. A rope is attached to the crate and held at angle theta 28.
    14·1 answer
  • A 70kg car drives through a curve with radius 50m. What is the minimum angle the road should be tilted to keep the car on the ro
    10·1 answer
  • What type of energy is stored in solar panels
    13·1 answer
  • Calculate the momentum of a 6 kg ball thrown at 20 m/s by a 3 newton<br> force. *
    15·1 answer
  • Which of the following is a true statement about work?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!