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MA_775_DIABLO [31]
2 years ago
6

The solid shaft with a 20 mm radius is used to transmit the torques applied to the gears. Determine the maximum torsional shear

stress developed in in the shaft.
Physics
1 answer:
AysviL [449]2 years ago
3 0

Answer:

τ = (7.96 x 10⁴ m⁻³)T

This is the expression for maximum allowable shear stress in terms of the maximum torque applied in Nm.

Explanation:

The maximum allowable shear stress on the solid shaft can be given by the torsional formula as follows:

τ = Tc/J

where,

τ = Maximum Allowable Shear Stress = ?

T = Maximum Torque Applied to the Shaft

c = maximum distance from center to edge = radius in this case = 20 mm = 0.02 m

J = Polar Moment of inertia = πr⁴/2 = π(0.02 m)⁴/2 = 2.51 x 10⁻⁷ m⁴

Therefore,

τ = T(0.02 m)/(2.51 x 10⁻⁷ m⁴)

<u>τ = (7.96 x 10⁴ m⁻³)T</u>

<u>This is the expression for maximum allowable shear stress in terms of the maximum torque applied in Nm.</u>

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(a) The time for the capacitor to loose half its charge is 2.2 ms.

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t = 1.59 ms

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