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nordsb [41]
3 years ago
7

The waste products of combustion leave the internal combustion engine through the?

Chemistry
2 answers:
nikklg [1K]3 years ago
4 0
B. Intake valve is the correct answer
kolbaska11 [484]3 years ago
3 0
B. Intake Valve
I just took the Penn Foster test and it was correct.
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A small hole in the wing of a space shuttle requires a 20.7-cm² patch.
cricket20 [7]

The Patch's area of the space shuttle in km² is 2.07 × 10⁻⁹ km²

Given, that a space shuttle requires a 20.7 cm² patch

We have to convert the patch's area from cm² into km².

Unit conversion is a method in which we multiply or divide with a particular numerical factor and then finally round off to the nearest significant digits.

Patch area of the space shuttle is 20.7 cm²

1 cm = 0.00001 km

or, 1 cm² = (0.00001 km)²

or,  1 cm² = 10⁻¹⁰km²

20.7 cm² = 20.7 ×  10⁻¹⁰km²

20.7 cm² = 2.07 × 10⁻⁹ km²

The patch area in square kilometers is 2.07 × 10⁻⁹ km²

To learn more about unit conversion, visit: brainly.com/question/11543684

#SPJ4

8 0
2 years ago
69 whenever organic matter is decomposed under oxygen-free(anaerobic) conditions, methane is one of the products. thus,enormous
Lina20 [59]
The solution is as follows:

The problem would only need the information of 5,600 EJ for the known sources of methane. The molar mass of methane is 16 g/mol.

802 kJ/mol(1000 J/ 1 kJ)(1 mol/16 g)(1000 g/1 kg)(x kg) = 5,600 EJ(10¹⁸ J/1 EJ)
Solving for x,
<em>x = 1.18×10¹⁴ kg of natural gas or methane</em>
8 0
4 years ago
For the reaction
Pepsi [2]

Answer:

Mass of Na₂CrO₄ =  5.75 g

Explanation:

First of all we will write the balance chemical equation.

2AgNO₃ + Na₂CrO₄     →    Ag₂CrO₄  +  2NaNO₃

Now we will calculate the moles of AgNO₃.

Number of moles = mass / molar mass

Molar mass of AgNO₃ = 107.87 + 14 + 3× 16 =  169.87 g/mol

Number of moles = mass / molar mass

Number of moles = 12.1 g / 169.87 g/mol = 0.071 mol

Now we will compare the moles of AgNO₃ and  Na₂CrO₄ from balance chemical equation.

                        AgNO₃    :     Na₂CrO₄

                          2            :           1

                          0.071     :           1/2× 0.071 = 0.0355

Now we will calculate the mass of Na₂CrO₄.

Molar mass of Na₂CrO₄ = 23×2 + 52 + 16×4 = 162 g/mol

Mass of Na₂CrO₄ = number of moles  ×  molar mass

Mass of Na₂CrO₄ =  0.0355 mol ×  162 g/mol

Mass of Na₂CrO₄ =  5.75 g

3 0
3 years ago
A sample of 10.0 grams of carbon dioxide gas is contained in a tank with a volume of 6.0 L so that the pressure inside the tank
Snezhnost [94]

Answer:

49°C

Explanation:

Let's apply the Ideal Gases Law in order to solve this question:

P . V = n . R . T

Pressure = 1 atm

Volume = 6 L

n = number of moles → 10 g. 1mol /44g = 0.227 moles

R = Ideal Gases Constant

We replace data: 1 atm . 6 L = 0.227 mol . 0.082 . T

6 atm.L / ( 0.227 mol . 0.082) = T

T° = 322 K

We convert T° from K to °C → 322 K - 273 = 49°C

7 0
3 years ago
What is a rule for determining the mass number of an atom or ion​
Dennis_Churaev [7]

Answer:

The number of electrons in a neutral atom is equal to the number of protons. The mass number of the atom (M) is equal to the sum of the number of protons and neutrons in the nucleus.

sorry if im wrong

Explanation:

5 0
3 years ago
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