Clearly H2 is in gaseous state as could be seen from (g) written with it which tells state of the product
<span>Reaction of ethane combustion:
2C2H6 (g) + 7O2 (g) ----> 4CO2 (g) + 6H2O
According to the reaction, we can see that </span>C2H6 and CO2 have following stoichiometric ratio:
n(C2H6) : n(CO2) = 2 : 4
If we know the number of moles of ethane we can calculate moles of carbon dioxide:
2 x n(CO2) = 4 x n(C2H6)
n(CO2) = 2 x n(C2H6)
n(CO2) = 2 x 5.4 = 10.8 mole of CO2 <span>are produced</span>
I beleive its A but not very sure though. If im wrong sorry. But if im right I hope it helps (:
No of moles= mass/atomic mass
no moles of potassium= 65g/39.8= 1.6moles
