Question

Propane can be turned into hydrogen by the two-step reforming process. In the first step, propane and water react to form carbon monoxide and hydrogen: C3Hg(g)+3 H20()- 3 CO(g)+7 H2(g) In the second step, carbon monoxide and water react to form hydrogen and carbon dioxide: CO(g)+H20(g)H2(9)+CO2(g) Write the net chemical equation for the production of hydrogen from propane and water. Be sure your equation is balanced.

Answer 1

Answer: The net chemical reaction:

$C_3H_8(g)+6H2_O(g)\rightarrow 10H_2(g)+3CO_2(g)$

Explanation:

Step  1 : Propane reacts with water to form carbon monoxide and hydrogen gas

$C_3H_8(g)+3 H_2O(g)\rightarrow 3 CO(g)+7 H_2(g)$...[1]

Step 2 : carbon monoxide formed in above step reacts with water tio form hydrogen gas and carbon dioxide.

$CO(g)+H_2O(g)\rightarrow H_2(g)+CO_2(g)$...[2]

On Adding [1] and 3 × [2] we get overall balanced chemical reaction for the production of hydrogen from propane and water:

$C_3H_8(g)+6H_2O(g)\rightarrow 10H_2(g)+3CO_2(g)$

1 mole of propane reacts with 6 moles of water vapor to gve 10 moles of hydrogen gas and 3 moles of carbon dioxide.