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MariettaO [177]
3 years ago
6

What is the volume of 45.0 grams of nitrogen monoxide , NO

Chemistry
1 answer:
gladu [14]3 years ago
3 0

Answer:

V=37.05\ L

Explanation:

Given that:

Mass of NO, m = 45.0 g

Molar mass of NO, M = 30.01 g/mol

Temperature = 20.0 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (20.0 + 273.15) K = 293.15 K

V = ?

Pressure = 740 mm Hg

Considering,  

n=\frac{m}{M}

Using ideal gas equation as:

PV=\frac{m}{M}RT

where,  

P is the pressure

V is the volume

m is the mass of the gas

M is the molar mass of the gas

T is the temperature  

R is Gas constant having value = 62.36367 L. mmHg/K. mol

Applying the values in the above equation as:-

740\times V=\frac{45.0}{30.01}\times 62.36367\times 293.15

740V=\frac{822685.94372}{30.01}

V=37.05\ L

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8 0
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A mixture of water and graphite is heated to 600 k in a 1 l container. when the system comes to equilibrium it contains 0.15 mol
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(missing in Q) : Calculate the concentration of CO & H2 & H2O when the system returns the equilibrium???

when the reaction equation is:

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∴ Kc = [H2] [CO] / [H2O]

and we have Kc = 0.0393 (given missing in the question)

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that means that 0.15 mol H2 gives 0.15 mol of H2O

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            [H2O]          [H2]        [CO]

initial 0.57 + 0.15      0               0.15

change  -X                +X              +X

Equ   (0.72-X)             X            (0.15+X)

by substitution:

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             = 0.622 M


8 0
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