The hormone adrenaline can affect only cells with

How many moles are in a sample of 1.52 x 1024 atoms of mercury (Hg)?

OLEGan [10]

The answer is:

2.5 moles

The explanation:

when avogadro's number = 6.02 * 10^23

and when 1 mole of the sample will give → 6.02*10^23 atoms

So, ??? mole of the sample will give→ 1.52 x 10^24 atoms

∴ number of moles = (1.52 X 10^24) * 1 mole / (6.02X10^23)

= 2.5 moles

8 0

3 years ago

When 1.5 grams of magnesium burns, how many grams of magnesium oxide will be formed?

SashulF [63]

The balanced chemical reaction for this would be written as:

2Mg + O2 = 2MgO

We use this reaction and the amount of the reactant given to calculate for the amount of magnesium oxide that is produced. We do as follows:

1.5 g Mg (1 mol / 24.31 g) ( 2 mol MgO / 2 mol Mg ) (40.30 g /1 mol ) = 2.49 g MgO produced

6 0

3 years ago

AGO H2SO4 (aq) Al(SO4)3(aq) H28) fe Cl218) FeCl38<br>

Rina8888 [55]

Answer:

2Al + 3H2SO4 → Al2(SO4)3 + 3H2

2Fe + 3Cl2 → 2FeCl3

Explanation:

1. (SO4) 3 you see this 3 it means that 3 must be behind H2SO4. So now it's 3H2SO4.

2. If 3 is now behind one H2, it must be behind the other.

So now it's 3H2.

3. Al2 (SO4) 3 has 2 ahead of Al which means there will be 2Al in the reactants.

1. FeCl3 has 3 ahead of Cl, and Cl2 has 2. Which means that behind FeCl3 goes 2, and behind Cl2 goes 3 so now we have equated all Cl.

2. Since it is now 2FeCl3, we know that there must be 2 in the second Fe. It's 2Fe now.

7 0

3 years ago

Can someone help me please ;)<br> Will be marking someone brainliest !<br> Thank you

mote1985 [20]

Answer: C

Explanation:

4 0

4 years ago

Find the new concentration of a solution if 25.0 mL of water is added to 125.0 mL of 0.150 M NaCl solution. What is the final vo

lesantik [10]

Answer : The correct answer is New concentration = 0.125 M and final volume = 0.150 M

Given :

Molarity of NaCl solution = 0.150 M volume of NaCL solution = 125 mL

Volume of water added = 25 mL

1) Final volume = ? 2) New concentration = ?

1) To find the final volume :

New volume = volume of NaCl solution + volume of water added

= 125 mL + 25 mL

= 150 mL

Converting this final volume from mL to L

1 L = 1000 mL

$Final volume = 150 mL * \frac{1 L}{1000 mL }$

Final volume = 0.150 L

2) To find new concentration :

Following steps can be used :

a) To find mole of NaCl :

Mole of NaCl can be calculated using molarity formula . Molarity can be defined as mole of solute present in Liter of solution (volume ) .It represents Concentration of solution . It used unit as M or $\frac{mol}{L}$ . It can be expressed as :