Question

A student stands at the edge of a cliff and throws a stone horizontally over the edge with a speed of v0 = 15.0 m/s. The cliff is h = 49.0 m above a flat, horizontal beach as shown in the figure. (a) What are the coordinates of the initial position of the stone? x0 = m y0 = m (b) What are the components of the initial velocity? v0x = m/s v0y = m/s (c) Write the equations for the x- and y-components of the velocity of the stone with time. (Use the following as necessary: t. Let the variable t be measured in seconds. Do not include units in your answer.) vx = vy = (d) Write the equations for the position of the stone with time, using the coordinates in the figure. (Use the following as necessary: t. Let the variable t be measured in seconds. Do not state units in your answer.) x = y = (e) How long after being released does the stone strike the beach below the cliff? s (f) With what speed and angle of impact does the stone land? vf = m/s ? =

Answer 1

Answer:

(a) x0 = 0m and y0 = 49.0m

(b) Vox = 15.0m/s Voy = 0m/s

(c) Vx = Vo = 15.0m/s and Vy = -gt

(d) X = 15.0t and y = 49.0 - 4.9t²

(e) t = 3.16s

(f) Vf = 34.4m/s

Explanation: