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igor_vitrenko [27]
3 years ago
12

A student stands at the edge of a cliff and throws a stone horizontally over the edge with a speed of v0 = 15.0 m/s. The cliff i

s h = 49.0 m above a flat, horizontal beach as shown in the figure. (a) What are the coordinates of the initial position of the stone? x0 = m y0 = m (b) What are the components of the initial velocity? v0x = m/s v0y = m/s (c) Write the equations for the x- and y-components of the velocity of the stone with time. (Use the following as necessary: t. Let the variable t be measured in seconds. Do not include units in your answer.) vx = vy = (d) Write the equations for the position of the stone with time, using the coordinates in the figure. (Use the following as necessary: t. Let the variable t be measured in seconds. Do not state units in your answer.) x = y = (e) How long after being released does the stone strike the beach below the cliff? s (f) With what speed and angle of impact does the stone land? vf = m/s ? =

Physics
1 answer:
ankoles [38]3 years ago
8 0

Answer:

(a) x0 = 0m and y0 = 49.0m

(b) Vox = 15.0m/s Voy = 0m/s

(c) Vx = Vo = 15.0m/s and Vy = -gt

(d) X = 15.0t and y = 49.0 - 4.9t²

(e) t = 3.16s

(f) Vf = 34.4m/s

Explanation:

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Answer:

200,000 and 20,000,000

Explanation:

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I hope this helps!

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Answer:

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This question is incomplete

Explanation:

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The eyepiece's focal length was provided in the question as 0.38 m.

NOTE: Magnification can be described as the power of an instrument (in this case telescope) to enlarge an object. It has no unit and thus the two focal lengths mentioned in the formula above must be in the same unit (preferably meters since one of them is in meters already).

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