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Oliga [24]
3 years ago
6

Which is a perfect square a. 6^1 b. 6^2 c. 6^3 d. 6^5 (need answer now pls)

Mathematics
1 answer:
Bas_tet [7]3 years ago
6 0
Hello there! 6^1 is not a perfect square. It's basically it's own number and 6 is not a perfect square. Therefore, A is out. 6^3 (216) is cubed, not squared, so C is out as well. Just by looking at the exponents, 6^2 is squared and 36 is a perfect square, so the answer is B: 6^2.
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dybincka [34]
In one lemonade bottle, there would be 2000mL. (1L = 1000mL)
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I’ll brainliest you please help me
Tanya [424]
X= 75
y= 105
this is because x is equal to the angle with 75, y us 105 because 180-75=105. 180 is found because the angle of a line is 180
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An inscribed angle measures 48°; so, the intercepted arc measures 24°. <br> True <br> False
tigry1 [53]

False


The arc is double the inscribed angle.

Arc = 2*48 = 96

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8. Which expression is greatest? Justify your answer.<br> a. 4 X -5<br> b. -5 + 4<br> c. -4- (-5)
vladimir1956 [14]

Answer:

c

Step-by-step explanation:

i think this is the greatest because if you solve all of the expressions you will find out that this is the greatest.

a.4×-5=-20

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therefore 1 is the greatest so the expression c is the greatest.

I hope this helps

3 0
3 years ago
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NEED MATH HELP QUICK!
Korolek [52]

Answer:

Minimum = 14

Q_1=23

Median = 32

Q_3=49

Maximum = 65

Step-by-step explanation:

<u>Step 1: </u>Put your numbers in ascending order (from smallest to largest). For this particular data set, the order is

14, 18, 28, 29, 32, 44, 48, 50, 65

<u>Step 2:</u> Find the minimum and maximum for your data set. Now that your numbers are in order, this should be easy to spot.

Minimum = 14

Maximum = 65

<u>Step 3: </u>Find the median. The median is the middle number. The middle number in your list is 32, so

Median = 32

<u>Step 4: </u>Place parentheses around the numbers above and below the median.

(14, 18, 28, 29), 32, (44, 48, 50, 65)

<u>Step 5: </u>Find Q1 and Q3. Q1 can be thought of as a median in the lower half of the data, and Q3 can be thought of as a median for the upper half of data.

First quartile

\bf{Q_1=\dfrac{18+28}{2}=\dfrac{46}{2}=23}

Third quartile

\bf{Q_3=\dfrac{48+50}{2}=\dfrac{98}{2}=49}

<u>Step 6:</u> Write down your summary found in the above steps.

Minimum = 14

Q_1=23

Median = 32

Q_3=49

Maximum = 65

5 0
4 years ago
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