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2 years ago

6

Robot a new skateboard that was on sale the original price of the skateboard was $60 the store had marked it down by $20 percent

and will had a 25% off coupon as well
what was the price of the skateboard before tax

A. $12
B. $24
C. $36
D. $48

2 answers:

Westkost [7]2 years ago

4 0

Answer: it is c 36$

Step-by-step explanation:

Vera_Pavlovna [14]2 years ago

3 0

The answer is the letter C.$36

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Shauna spent $175 on a pair of shoes.She spent 1/9 of the remaining money on a shirt.If he still had 4/7of his moneyleft,how muc

KIM [24]

Answer:

$490

Step-by-step explanation:

Shauna spent $175 on a pair of shoes.

She spent 1/9 of the remaining money on a shirt.

If he still had 4/7 of his money left,how much did he have at first ?

Solution:

Let at first, Shauna have = $x$

Money spent on a pair of shoes = $175

Remaining money = $x-175$

<u>As she spent 1/9 of the remaining money on a shirt.</u>

Money spent on shirt = $\frac{1}{9} \times(x-175)=\frac{x}{9} -\frac{175}{9}$

As he still had $\frac{4}{7}$ of his money left:-

Money left = $\frac{4}{7}\ of\ his\ money=\frac{4x}{7}$

Money left with Shauna = Total money, she had at first -(Money spent on a pair of shoes + Money spent on shirt )

$\frac{4x}{7} =x-(175+{\frac{x}{9} -\frac{175}{9} )\\\\\\$

$\frac{4x}{7} =x-(\frac{175}{1} -\frac{175}{9} +\frac{x}{9} )\\\\ \frac{4x}{7} =x-(\frac{1575-175}{9} +\frac{x}{9} )\\\\ \frac{4x}{7}=x-(\frac{1400}{9} +\frac{x}{9} )\\ \\ \frac{4x}{7}=x-\frac{1400}{9} -\frac{x}{9}$

Subtracting both sides by $x$ and adding both sides by $\frac{x}{9}$

$\frac{4x}{7} -x+\frac{x}{9} =-\frac{1400}{9} -x+\frac{x}{9} +x-\frac{x}{9}$

Taking LCM of 7 and 9, we get 63

$\frac{36x-63x+7x}{63} =-\frac{1400}{9} \\ \\ -\frac{20x}{63}=-\frac{1400}{9}$

Adding both side by -

$\frac{36x-63x+7x}{63} =-\frac{1400}{9} \\ \\ \frac{20x}{63}=\frac{1400}{9}$

By cross multiplication:

$20x\times9=1400\times63\\180x=88200\\$

Dividing both sides by 180

$x=490$

Therefore, total $490, she had at first.

3 0

3 years ago

In figure AB and CD bisect each other at O. State the 3 pairs of equal parts in ∆AOC and ∆BOD. Is ∆AOC ≅ ∆BOD? Give reasons

GuDViN [60]

Answer:

SEE EXPLANATION

Step-by-step explanation:

$In\:\triangle AOC \:\&\:\triangle BOD$

$AO \cong OB.... (given)$

$\angle AOC \cong\angle BOD$

$(vertical \: \angle s)$

$CO \cong OD.... (given)$

$\therefore \triangle AOC \:\cong\:\triangle BOD$

$(SAS \: postulate)$

So, the 3 pairs of equal parts in ∆AOC and ∆BOD are:

$AC = BD$

$m\angle OAC = m\angle OBD$

$m\angle OCA = m\angle ODB$

7 0

3 years ago

Pls answer this correctly

Bingel [31]

Answer:

4 balloon would expect to be orange

3 0

3 years ago

Company A offers a starting salary of $28000 with a raise of $3000 each year, Company B offers a starting salary of $36000 with

telo118 [61]

We can conclude that both will intersect at a certain angle, depending on this algorithm I created.

28000 + 3000x = 36000 + 2000x

The f(x) intercept for g(x) is = 9 and -9

If you square this by light, the arithmetic of 9x+5x=21s(x)

Thus we can simply and get 11 years.

7 0

3 years ago

Read 2 more answers

I’m kinda stuck on here on how to do this .... how am I suppose to go down again if it’s not gonna be on the line.

mars1129 [50]

To graph the new shape, you must move each vertex down 3 units. This causes Q to become (1, 0), L to become (5, -2), and Q to become (1, 0). These values can be found by simply counting down by three for each point.

3 0

3 years ago